Mc012-2.jpg ........................ 10/90%= 11.1111111111111
Answer:
(a-b, c)
Step-by-step explanation:
The midpoints of the two diagonals are the same, so we have ...
(P + (-a, 0))/2 = (O +(-b, c))/2
Multiplying by 2 and subtracting (-a, 0), we get ...
P = (0, 0) +(-b, c) -(-a, 0)
P = (a-b, c)
Answer: Yes, a triangle can have sides of those lengths.
Step-by-step explanation:
