A block of ice with mass 5.50 kg is initially at rest on a frictionless, horizontal surface. A worker then applies a horizontal
force F⃗ to it. As a result, the block moves along the x-axis such that its position as a function of time is given by x(t)
1 answer:
Answer:
x ( t ) = F / 5.5 t²
Explanation:
acceleration dv / dt = F / 5.5
dv = F / 5.5 dt
integraring on both sides
v = F / 5.5 t + c
when t = 0 , v = 0
c = 0
v = F / 5.5 t
ds / dt = F / 5.5 t
integrating on both sides
s = F / 5.5 t² + c₁
when t = 0 , s = 0
c = 0
so
x ( t ) = F / 5.5 t²
This is the required relation.
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