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Gekata [30.6K]
3 years ago
12

A block of ice with mass 5.50 kg is initially at rest on a frictionless, horizontal surface. A worker then applies a horizontal

force F⃗ to it. As a result, the block moves along the x-axis such that its position as a function of time is given by x(t)
Physics
1 answer:
AlekseyPX3 years ago
3 0

Answer:

x ( t )  = F / 5.5  t²

Explanation:

acceleration dv / dt = F / 5.5

dv = F / 5.5  dt

integraring on both sides

v =  F / 5.5  t + c

when t = 0 , v = 0

c = 0

v =  F / 5.5  t

ds / dt  = F / 5.5  t

integrating on both sides

s = F / 5.5  t² + c₁

when t = 0 , s = 0

c = 0

so

x ( t )  = F / 5.5  t²

This is the required relation.

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7 0
3 years ago
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I am Lyosha [343]

Answer:

it's b

Explanation:

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6 0
2 years ago
Read 2 more answers
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3 0
2 years ago
A transformer has a primary coil with 375 turns of wire and a secondary coil with 1,875 turns. An AC voltage source connected ac
Sonbull [250]

Answer:

The rms voltage (in V) measured across the secondary coil is 459.62 V

Explanation:

Given;

number of turns in the primary coil, Np = 375 turns

number of turns in the secondary coil, Ns = 1875 turns

peak voltage across the primary coil, Ep = 130 V

peak voltage across the secondary coil, Es = ?

\frac{N_P}{N_s} = \frac{E_p}{E_s} \\\\E_s = \frac{N_sE_p}{N_p} \\\\E_s = \frac{1875*130}{375} \\\\E_s = 650 \ V

The rms voltage (in V) measured across the secondary coil is calculated as;

V_{rms} = \frac{V_0}{\sqrt{2} } = \frac{E_s}{\sqrt{2} } \\\\V_{rms} = \frac{650}{\sqrt{2} } = 459.62 \ V

Therefore, the rms voltage (in V) measured across the secondary coil is 459.62 V

7 0
3 years ago
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NNADVOKAT [17]

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