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tiny-mole [99]
3 years ago
14

Ill mark the brainliest pls lmk what answer ty

Physics
1 answer:
Alla [95]3 years ago
3 0

2800 m

<h3>Further explanation</h3>

Given

time = 80 s

average velocity = 35 m/s

Required

total distance before it broke down

Solution

Average velocity : total displacement : total time

Can be formulated

avg velocity = Δx : Δt

Input the value :

Δx=avg velocity x Δt

Δx = 35 m/s x 80 s

Δx = 2800 m

In addition, if we are asking for velocity, we must know the starting and ending points (displacement)

But if we calculate the total distance, what is written is the average speed

avg speed = total distance : total time

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3 0
3 years ago
The objective lens and the eyepiece of a telescope are spaced 85 cm apart. If the eyepiece is123 D what is the total magnificati
dedylja [7]

Answer:

The magnification would be "103.55". A further explanation is given below.

Explanation:

The given values are:

Distance between lens and eyepiece,

L = 85 cm

Eyepiece is,

= 123 D

Now,

The refractive power of eye piece will be:

⇒ \frac{1}{f_e}=123D

   f_e=\frac{1}{123D}

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The length of the telescope will be:

⇒ L=f_0+f_e

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On substituting the values, we get

⇒     =85-0.813

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5 0
2 years ago
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