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yan [13]
3 years ago
11

PHYSICAL SCIENCE: What are some methods used to control the types and sources of pollution?

Physics
1 answer:
irina [24]3 years ago
3 0

Gaseous emissions are industrial products such as sulfur dioxide, carbon monoxide, and oxides of nitrogen also released during various manufacturing operations. Particulate control. Methods for particulate control tend to operate on a common principle.

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Two parallel circular plates with radius carrying equal-magnitude surface charge densities of are separated by a distance of How
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Answer:

I guess it is A. I am not sure

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3 years ago
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Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface. When she lands on Noveria, a distant planet in
Anastasy [175]

Answer:

Acceleration of gravity on Noveria = 4.4 m/s²

Explanation:

Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface.

We have weight, W = mg

Acceleration due to gravity, g = 9.81m/s²    

799 = m x 9.81

Mass of Shepard, m = 81.45 kg            

She lands on Noveria, a distant planet in our galaxy, she weighs 356 N.

We have weight, W = mg'

                 356 = 81.45 xg'

Acceleration of gravity on Noveria, g' = 4.4 m/s²

6 0
4 years ago
The transmission of heat requiring the movement of a liquid or a gas is
AysviL [449]

Answer:

convection

Explanation:

7 0
3 years ago
The voltage across the diode indicates the energy given to charge carriers (electrons and holes, but more about that later in th
Elis [28]

Answer:

the charge carriers have an energy 2.8 10⁻¹⁹ J

Explanation:

The energy in a diode is conserved so the energy supplied must be equal to the energy emitted in the form of photons.

The energy of a photon is given by the Planck expression

             E = h f

the speed of light, wavelength and frequency are related

             c = λ f

we substitute

             E = \frac{h \ c}{\lambda}

a red photon has a wavelength of lam = 700 nm = 700 10⁻⁹ m

we calculate the energy

              E = 6.626 10⁻³⁴  3 10⁸/700 10⁻⁹

              E = 2.8397 10⁻¹⁹J

therefore the charge carriers have an energy 2.8 10⁻¹⁹ J,

3 0
3 years ago
A small metal sphere has a mass of 0.14 g and a charge of -22.0 nc . it is 10 cm directly above an identical sphere with the sam
Allushta [10]
For this problem, we use the Coulomb's law written in equation as:

F = kQ₁Q₂/d²
where
F is the electrical force
k is a constant equal to 9×10⁹ 
Q₁ and Q₂ are the charge of the two objects
d is the distance between the two objects

Substituting the values:

F = (9×10⁹)(-22×10⁻⁹ C)(-22×10⁻⁹ C)/(0.10 m)²
F = 0.0004356 N
4 0
3 years ago
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