Question

As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 46.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 5.80 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following.
a. The salmon's acceleration
b. The magnitude of the force F during this interval N

Answer 1

Answer:

a

   $a = 12.32 \ m/s^2$

b

 $F = 1017.52 \ N$

Explanation:

From the question we are told that

  The  length of the Chinook salmon is  $l = 1.50 \ m$

   The mass of the Chinook salmon is $m = 46.0 \ kg$

   The  upward velocity in water is  $u = 3.00 \ m/s$

    The  upward velocity in air is $v = 5.80 \ m/s$

   

Generally from kinematic equations

     $v^2 = u^2 + 2as$

=>    $5.80^2 = 3.00^2 + 2 * a * [ [\frac{2}{3} * l ]$

=>   $5.80^2 = 3.00^2 + 2 * a * [ [\frac{2}{3} * 1.5 ]$

=>   $5.80^2 = 3.00^2 + 2 * a * [1 ]$      

=>    $a = 12.32 \ m/s^2$

Generally magnitude of the force F during this interval in N  is mathematically represented as

      $F = m (a + g )$

=>    $F = 46.0 (12.32 + 9.8 )$

=>    $F = 1017.52 \ N$