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4 years ago

How many electrons circulate each second through the cross section of a conductor, which has a current intensity of 4A.

Physics

1 answer:

guajiro [1.7K]4 years ago

8 0

Answer:

2.5×10¹⁹

Explanation:

4 C/s × (1 electron / 1.60×10⁻¹⁹ C) = 2.5×10¹⁹ electrons/second

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How long would it take for a rock falling 97.2 m/s to reach the ground from 100 meters

mote1985 [20]

Answer;

velocity(v) = 97.2 m/s ,

distance (S) = 100 m

determine time(t) = ?

We know that,

distance (S) = velocity(v) × time(t)

So, time (t) = distance ÷ velocity

= 100 ÷ 97.2

<em>I hope this will help you.</em>

5 0

4 years ago

What provides most of the force to allow the runners to move?

kobusy [5.1K]

Answer:

When you are running the most important force that you should understand is friction. Friction is a force that opposes movement between two objects, but for runners friction makes you faster. Friction gives you a better and more efficient way to use your energy into speed.

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3 years ago

A block slides to a stop as it goes 47 m across a level floor in a time of 6.35 s. a) What was the initial velocity? b) What is

UNO [17]

Answer :

(a) The initial velocity is, 14.8 m/s

(b) The acceleration is, $-2.33m/s^2$

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 0 s

u = initial velocity

t = time = 6.35 s

a = acceleration

The equation 1 will be:

$0=u+a(6.35}$

$u=-6.35a$ ..........(2)

By the 2nd equation of motion,

$s=ut+\frac{1}{2}at^2$ ...........(3)

where,

s = distance = 47 m

Now substitute equation 2 in 3, we get:

$47=(-6.35a)\times (6.35)+\frac{1}{2}\times a\times (6.35)^2$

By solving the term, we get:

$a=-2.33m/s^2$

The acceleration is, $-2.33m/s^2$

Now we have to calculate the initial velocity.

Using equation 2, we gte:

$u=-6.35a$

$u=-6.35s\times (-2.33m/s^2)$

$u=14.8m/s$

The initial velocity is, 14.8 m/s

5 0

3 years ago

Question If a force of 2N is used to move a box 1 meter, how much work was done to move the box?

Sunny_sXe [5.5K]

Answer:

I assume that the force of 2N is applied along the direction of motion and was applied for the whole 1 meter, the formula of work is this; Work = force * distance * cosθ where θ is zero degrees. Plugging in the data to the formula;

Explanation:

Work = 2N * 1m * cos 0º.

Work = 2N * 1m * 1

Work = 2Nm

Work = 2 joules

7 0

3 years ago

Convert <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%280.779mg%29%28min%29%7D%7BL%7D" id="TexFormula1" title="\frac{(0.779mg)(mi

Orlov [11]

The number converted is $0.0467 \frac{(kg)(s)}{m^3}$