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valina [46]
3 years ago
13

Which is more dangerous to living things, gamma rays or X-rays? Explain.

Physics
1 answer:
KiRa [710]3 years ago
7 0

Answer and Explanation:

Both gamma rays and X- rays are dangerous to living things but when there is comparison between gamma and X- rays gamma rays are more dangerous to living things because it has more energy as its frequency is  high as compared to X-rays because X-rays have longer wavelength than gamma rays so the gamma rays are more dangerous than x rays to living things

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during a baseball game you are running home and slide into home plate. However you come up short and you are tagged out. Which f
vovangra [49]

Answer:1 because

Explanation: it’s pointing to the earth and gravity

Pulls things down to earth

3 0
3 years ago
A force of 100 newtons is used to move an object a distance of 15 meters with a power of 25 watts. Find the
valentina_108 [34]


work is distance * force so 15*100=1500

and to find time you know power = diastance * force / time

so 25=15*100/t

25=1500/t

25/1500=t

.016=time


5 0
3 years ago
A horizontal force of 100 N is required to push a 50 kg crate across a factory floor at a constant speed. What is the accelerati
luda_lava [24]

Answer:

a = 2m/s^2

Explanation:

Force (F) = 100 N

Mass (m) = 50 kg

Here,

F = m×a

100 = 50 × a

a = 100÷50

a = 2m/s^2

Thus, the acceleration on the cart is a = 2m/s^2

-TheUnknownScientist

6 0
3 years ago
Most people can detect frequencies as high as 20 000 Hz. Assuming the speed of sound in air is 345 m/s, determine the wavelength
Gekata [30.6K]

Wavelength = speed / frequency

(345 m/s) / (20,000 Hz) = 0.017 m

6 0
3 years ago
Read 2 more answers
When the distance between two stars decreases by one-third, the force between them
pashok25 [27]

Answer:

the force will increase by a factor 2.25

Explanation:

The gravitational force between the two stars is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two stars

r is the distance between the stars

If the distance is decreased by one-third, it means that the new distance is 2/3 of the previous distance

r'=\frac{2}{3}r

So the new force will be

F'=G\frac{m_1 m_2}{(\frac{2}{3}r)^2}=\frac{9}{4} G\frac{m_1 m_2}{r^2}=2.25 F

So, the force will be 2.25 times the previous value.

4 0
4 years ago
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