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finlep [7]
3 years ago
15

Quadratic Formula and the two solutions I would get

Mathematics
1 answer:
icang [17]3 years ago
5 0

A quadratic equation is given by three parameters:

ax^2+bx+c=0

  • a is the quadratic coefficient, since it multiplies x^2
  • b is the linear coefficient, since it multiplies x
  • c is the numeric coefficient, since it's a pure number.

The quadratic formula states that the two (possible) solutions for a quadratic equation are

ax^2+bx+c=0 \iff x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

In your case, you have

a=8,\quad b=-10,\quad c=-1

So, your quadratic equation and its solving formula become

8x^2-10x-1=0 \iff x_{1,2} = \dfrac{10\pm\sqrt{100+32}}{16}=\dfrac{10\pm\sqrt{132}}{16}

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