Solve it by substitution. First let's rewrite the first equation (3x+4y=16) so we have y = something, then we'll substitue that in to the other equation.
3x+4y=16
4y=-3x+16
y=-3/4x+4
Now we can substitute this into the other equation.
<span>A. 1040
1040 is the form that you can itemized deductions which is where you deduct charitable contributions.
</span>
Is A & C.
Explanation:
A. Median for sea turtles:
The set is odd, so median is the middle number - 4
The koi set had 10, even number, so the median for the koi is the average of the 2 middle: 4+3=3.5
Turtles > koi
C. The ages of koi are more spread out - 10. The turtles are only 5.
A. P[TTTTH] = .55^4*.45 = .0412
<span>b. P[HHHT] = .45^4*.55 = .0226 </span>
<span>c. 1/.45 = 2.222 </span>
<span>d. 1/.55 = 1.818</span>
Answer: The first choice
Step-by-step explanation:
