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Zigmanuir [339]

3 years ago

9

a contractor finds that crew A takes 5 1/2 hours to construct a retaining wall and crew B can do the same job in 8 1/2 hours. if

crew A and crew B work together how long will it take them to construct the retaining wall

1 answer:

o-na [289]3 years ago

4 0

Answer:

14hrs

Step-by-step explanation:

5 1/2+8 1/2

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What is 3/5 as a simplified decimal

lisov135 [29]

3 divided by 5 equals 0.6

8 0

3 years ago

Read 2 more answers

Dan's car depreciates at a rate of 15% per year. By what percentage has Dan's car depreciated after 3 years?

Pavlova-9 [17]

The percentage of deprecation of the car in the third year is 38.59%.

<h3>What is deprecation?</h3>

Depreciation is the decline in the value of an asset as a result of wear and tear.

Deprecation in year 1 = 15%

Deprecation in year 2 = 15% x (100 - 15%) = 12.75%

Deprecation in year 3 = 15% x (85% - 12.75) = 10.84%

Sum of deprecation = 38.59%

To learn more about depreciation, please check: brainly.com/question/25552427

5 0

2 years ago

Help? high school pre cal

o-na [289]

Answer:

B. 2, -0.5

Step-by-step explanation:

Given the equation

$-2x^2+2=-3x$

Rewrite it as

$-2x^2+3x+2=0$

Graph the graph of the quadratic function $y=-2x^2+3x+2$

The grapg of this function is a parabola going downwards.

This parabola intersects the x-axis at points x = -0.5 and x = 2, so the solutions of the equation are x = -0.5 and x = 2

3 0

3 years ago

When truckers are on long-haul drives, their driving logs must reflect their average speed. Average speed is the total distance

bekas [8.4K]

a) $v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}$

The average speed is equal to the ratio between the total distance ( $d_{tot}$ and the total time taken ( $t_{tot}$ ):

$v=\frac{d_{tot}}{t_{tot}}$

the distance travelled by the trucker in the first 3 hour can be written as the time multiplied by the velocity:

$d_1 = (3 h)(60 mph)=180 mi$

So the total distance is

$d_{tot}=d_1 +d_2 = 180 mi+20 mi=200 mi$

The total time is equal to the first 3 hours + the time taken to cover the following 20 miles in the city:

$t_{tot}=3 h +t_2$

So, the equation can be rewritten as:

$v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}$

b) 0.50 h (half a hour)

Since we know the value of the average speed, $v=57.14 mph$ , we can substitute it into the previous equation to find the value of $t_2$ , the time the trucker drove in the city:

$v=\frac{200 mi}{3h +t_2}\\3h+t_2 = \frac{200 mi}{v}\\t_2 = \frac{200 mi}{v}-3h=\frac{200 mi}{57.14 mph}-3 h=0.50 h$

3 0

3 years ago

Can someone help me? IN NEED OF HELP!

bearhunter [10]

Answer:(updated)

2.4%

Step-by-step explanation:

$2.90-$2.83=$.07

.07/2.9=0.024137931(round to nearest ten<u>th</u>)=2.4%

or you can do 0.024137931*100 and get the same answer

Shout out to lameash66 (they helped me change my answer, thank you)

8 0

3 years ago