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Sati [7]
3 years ago
9

In the first quadrant you start at (7,3) and move 5 unit left

Mathematics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

That would be (2,3)

Step-by-step explanation:

When we're moving left in the coordinate plane, we are subtracting the x-coordinate by how much distance we move.

In this case, 7-5=2, so the new x-coordinate is 2, but the y-coordinate doesn't change since we're going horizontally and not vertically.

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Factorisation with this question, please help
charle [14.2K]

3( x - y )^2 - 2( x - y ) =

<em>(</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>)</em><em> </em>( 3( x - y) - 2 ) =

( x - y )( 3x - 3y - 2 )

8 0
3 years ago
Need help with this question
Degger [83]
It is a 100 degrees vertical angles are congruent

6 0
3 years ago
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5(x+6)-2x=3(x+10) solve for x
Drupady [299]

Answer:

x=all real numbers

Step-by-step explanation:

1. distribute: 5(x+6)-2x=3(x+10)

                      5x+30-2x=3x+30

2. combine like terms 3x+30=3x=30

3. these are equal therefore x=all real numbers

6 0
3 years ago
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Hannah is flying a kite with a trying that is 60 feet long. If Patricia is standing directly below the kite and 16 feet away fro
Nataly_w [17]

Answer:

74.5°

Step-by-step explanation:

Hannah, the kite and Patricia form the vertices of a right-angled triangle with the hypotenuse side the length of the string L = 60 feet and adjacent side the distance between Hannah and Patricia = d = 16 feet.

Let the angle between the string and the sand be Ф.

By trigonometric ratios,

cosФ = adjacent/hypotenuse

= d/L

= 16 feet/60 feet

= 0.2667

Ф = cos⁻¹(0.2667)

= 74.53°

≅ 74.5°

So, he angle between the string and the sand is Ф = 74.5°

7 0
3 years ago
How do you solve: 2(b - 5) + 7b-4
Alinara [238K]
2(b-5)+7b-4
Solve 2(b-5) to get 2b-10
Combine your like terms 2b-10+7b-4
Solve 2b+7b to get 9b
Solve -10+(-4) to get -14
So your answer is
9b-14

4 0
3 years ago
Read 2 more answers
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