Answer:
2cosAcos2A, 4sinAcos^2A
Step-by-step explanation:
cos3A+cosA
2cos((3A+A)/2)cos((3A-A)/2)
2cos(4A/2)cos(2A/2)
2cosAcos2A
sin3A+sinA
2sin((3A+A)/2)cos((3A-A)/2)
2sin(4A/2)cos(2A/2)
2sin2AcosA
4sinAcos^2A
Answer:
No, because as the x-values are increasing by a constant amount, the y-values are not being multiplied by a constant amount.
Step-by-step explanation:
We have a set of ordered pairs of the form (x, y)
If a function is exponential then the ratio between the consecutive values of y, is always equal to a constant.
This means that:
\frac{y_2}{y_1}=\frac{y_3}{y_2}=\frac{y_4}{y_3}=by1y2=y2y3=y3y4=b
This is: y_2=by_1y2=by1
Now we have this set of points {(-1, -5), (0, -3), (1, -1), (2, 1)}
Observe that:
\begin{gathered}\frac{y_2}{y_1}=\frac{-3}{-5}=\frac{3}{5}\\\\\frac{y_3}{y_2}=\frac{-1}{-3}=\frac{1}{3}\\\\\frac{3}{5}\neq \frac{1}{3}\end{gathered}y1y2=−5−3=53y2y3=−3−1=3153=31
Then the values of y are not multiplied by a constant amount "b"
Answer:
A slope of the line over the interval of [-6, -1] is ⅕ as illustrated in the graph above
Answer:
no lo entiendo lo que escribiste
