How do you get: a = -ω^2x from: a = -Aω^2sen(ωt) ?

Physics

1 answer:

Firdavs [7]4 years ago

8 0

Answer:

$x = Asin(\omega t)\\v = \frac{dx}{dt} = \omega Acos(\omega t)\\a = \frac{dv}{dt} = -\omega^2Asin(\omega t)= -\omega^2x$

You might be interested in

Question 29 (1 point)

bulgar [2K]

The answer is true. fluorescence demonstrates a sparkly like light beam and also can bounce off of other beams

8 0

3 years ago

What is the angle of reflection? Question 3 options: the angle that the incident ray makes with a line drawn perpendicular to th

Rama09 [41]

The angle of reflection is the angle that the reflected ray makes with a line drawn perpendicular to the reflecting surface.

6 0

4 years ago

A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 5.00s what is the speed of the mail

grandymaker [24]

The acceleration of gravity (on Earth) is 9.8 m/s² downward.

This means that every falling object gains 9.8 m/s more downward speed
every second that it falls.

In 5 seconds of falling, it gains (5 x 9.8 m/s) = 49 m/s of downward speed.

If it was already descending at 2.0 m/s at the beginning of the 5 sec,
then at the end of the 5 sec it would be descending at

(2 m/s + 49 m/s) = 51 m/s .

7 0

3 years ago

4 Points

lbvjy [14]

Answer:

Impulse = 322.5[kg*m/s], the answer is D

Explanation:

This method it is based on the principle of momentum and the amount of movement; and used to solve problems involving strength, mass, speed and time.

If units of the SI are used, the magnitude of the impulse of a force is expressed in N * s. however, when remembering the definition of the newton.

$N*S=(kg*m/s^{2} )*s = kg*m/s$