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ivann1987 [24]
3 years ago
15

A rock falls from a tower that is 320 feet high. As it is​ falling, its height is given by the formula h equals 320 minus 16 t s

quared . How many seconds​ (in tenths) will it take for the rock to hit the ground ​(hequals​0)?
Physics
1 answer:
RSB [31]3 years ago
4 0

Answer:

a. 4.5secs

Explanation:

From the question, the equation describing the height is given by

h(t)=320-16t^{2}\\

at the point when the rock hit the ground, the height,h will be zero.

Hence we can have

h(t)=320-16t^{2}\\\\at  h(t)=0\\0=320-16t^{2}\\hence \\320=16t^{2}\\t^{2}=\frac{320}{16}\\ t^{2}=20\\t=\sqrt{20}\\ t=4.47secs\\t=4.5sec\\

hence the rock will hit the ground in 4.5secs

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r = 3.64×10⁸ m

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