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aliina [53]
1 year ago
14

How can three resistors of resistance 2ohm,3ohm and 6ohm be connected to go live total resistance of (a) 4ohm,(b)1ohm?​

Physics
1 answer:
Sophie [7]1 year ago
8 0

\sf\large \green{\underbrace{\red{Answer⋆}}}:

(a) R2, R3 are parallel and series with R1

(b) R1, R2 and R3 are in parallel

Explanation:

\sf R_1 = 2  \: ohm\\  \sf R_2 = 3 \: ohm \\  \sf  R_3 = 6 \: ohm

(a)

\sf R_2   \: and \: R_3 \: are \: in \: parallel \\ \sf so \: let \: the \: total \: of \: R_2 \: and \: R_3 \: be \: R_a

\sf  \large \frac{1}{R_a}  =  \frac{1}{R_2}  +  \frac{1}{R_3}  \: as \: they \: are \: in \: parallel

\sf R_a =  \frac{1}{3}  +  \frac{1}{6}  \\  \\  \sf  \frac{1}{R_a}  =  \frac{2 + 1}{6}  \\  \\  \sf \frac{1}{R_a}   =  \frac{3}{6}  \\  \\  \sf  \frac{1}{R_a}  =  \frac{1}{2}  \\  \\  \sf R_a = 2 \: ohm

Ra and R1 is in series

And there total will be R

\sf R = R_a + R_1 \\  \\  \sf R = 2 + 2 \\  \\  \sf R = 4 \: ohm

(b)

\sf R_1 R_2 \: and \:R_3 \: are \: in \: parallel \: so \: total \: be \: R

\sf \frac{1}{R}  =  \frac{1}{R_1}  +  \frac{1}{R_2}  +  \frac{1}{R_3}  \\  \\   \sf   \frac{1}{R}  =  \frac{1}{2}  +  \frac{1}{3}  +  \frac{1}{ 6}  \\  \\  \sf  \frac{1}{R}  =  \frac{3+ 2 +1 }{6}  \\  \\  \sf  \frac{1}{R}  =  \frac{6}{6}  \\  \\  \sf R = 1 \: ohm

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At equilibrium the tension on the string due to the first mass is mathematically represented as

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The  frictional torque that must be exerted is mathematically represented as

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Initial total energy T = \frac{mgL}{2}

Now, when the rod is in horizontal position then final total energy will be as follows.

            T = \frac{1}{2}kx^{2} + I \omega^{2}

where,    I = moment of inertia of the rod about the end = \frac{mL^{2}}{3}

Also,    \omega = \frac{\nu}{L}

where,    \nu = speed of the tip of the rod

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The initial unstrained length is x_{o} = 0.1 m

Therefore, final length will be calculated as follows.

              x' = \sqrt{(0.2)^{2} + (0.1)^{2}} m

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So, according to the law of conservation of energy

       \frac{mgL}{2} = \frac{1}{2}kx^{2} + \frac{1 \times mL^{2}}{2 \times 3}(\frac{\nu}{L})^{2}

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There are three methods of heat travel:

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CONVECTION -- The transfer of heat due to the physical movement of an object. We can observe convection by looking at a pot of boiling water. Have you ever noticed that when a pot of water is boiling, the water seems to follow a vertical circular motion? This is convection. The parcel of heated water at the bottom of the pot rises, as it rises it gives off some of its heat. Because it loses some heat, the parcel is cooler than the surrounding water. It then sinks to the bottom of the pot and the process is started again. The path of the rising water followed by the sinking water traces out a circle.

RADIATION -- The transfer of heat by means of waves. This is the most difficult method of heat transfer to understand. Yet, we experience it every day. We feel the effects of radiation whenever we stand near a stove or oven which is being used. We feel the heat radiating from the stove or oven to our skin. Similarly, we have all been outside on a sunny, hot Summer's day. If we look up to the sky we can feel the rays of the Sun hitting our faces. The Sun is radiating its heat to the Earth.

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We can figure out what heat transfer process is influencing the air temperature at station 41001 by applying the three methods to our situation and then we can choose the one that seems most logical.

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