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3 years ago

What does 19.2 x 29.5 equal? Step by step instructions please

Mathematics

2 answers:

slava [35]3 years ago

5 0

Answer:

566.4

Step-by-step explanation:

do multipilication

lara31 [8.8K]3 years ago

4 0

Step-by-step explanation:

the solution at the right-hand side is what I want to explain at first I used the 5 to multiply the numbers above that is I used to 5 how to multiply 19.2 and that give me a value of 960 .Then , I used the 9 that is the number after the decimal point in 29.5 to multiply the 19.2 and it gave me 1728 then I use the 2 in 29.5 to multiply 19.2 and that gave me 384 . So ,when I add all numbers together it gave me 560 6.40

NB please at the right hand side I didn't put the Zero in the blank spaces . So, that's what I did at the left hand side

I hope it helps

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Answer:

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There are 112 seats in the school auditorium. There are 7 seats in each row. There are 70 people seated,filling up full rows of

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I think 11 rows are empty.

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Find the area of athletic field if it's length is 120cm and its width is 28cm .A. 397.6cm B. 3360cm C. 296 cm D. 4592cm E. 3356c

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a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

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3 years ago