Answer:
Step-by-step explanation:
Let's give this a go here. The volume formula for the shell method while rotating about a horizontal line is

where p(y) is the distance from the axis of rotation (the x-axis) to the center of the solid. This is a positive distance and it is just y.
h(y) is the horizontal height of the function. Our function starts at x = 0 and ends at the function itself, so h(y) = 3 + y^2.
In the shell method when rotating about a horizontal line, we need to use x = y equations, and y-intervals. Setting up our integral then:

We can simplify this a bit by distributing the y into the parenthesis:

Integrating gives us
from 2 to 3
Using the First Fundamental Theorem of Calculus:
which simplifies down to

64 x 100 = 6400
11 x x = 11x
I’ll solve this out for you
11x = 6400
Divide 11 from both sides
x = 581.8
Hope this helps!
.5 is really just 1/2 as a fraction so:
112 1/2 is fraction form
Answer: 61 unit^2
Step-by-step explanation:
ABCD is a rectangle with dimensions 12 by 11, for a total area of 132 (square units). Although I could determine the lengths of the parallel lines of the interior trapezoid from the data supplied, I'm lazy and decided, instead, to subtract from the total rectangle area the areas of the four right triangles formed outside the shaded area. The area of each triangle is (1/2)b*h, and we are given those dimensions on the figure.
The four triangle areas:
TriD = 36
TriA = 6
TriB = 20
TriC = 9
Total area = 71 square units.
Subtract this from the rectangle's area: 132 - 71 = 61 units^2
This is the area of the shaded trapezoid.
Answer:
I think it is A
Step-by-step explanation:
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