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Kazeer [188]
3 years ago
13

Let v1; v2; and v3 be three nonzero vectors in R3. Suppose v2 is not a scalar multiple of either v1 or v3 and v3 is not a scalar

multiple of either v1 or v2. Does it follow that every vector in R3 is is a linear combination of v1, v2, and v3?
Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

Not necessarily

Step-by-step explanation:

Lets take v1 = (1,0,0), v2 = (1,1,0) and v3 = (0,1,0). Neither of the vectors are a multiple of the other, however they dont generate R³ because for example the vector (0,0,1) is not a linear combination of v1, v2 and v3.

Not that, despite not being a multiple of v1 or v3, v2 is a linear combination of v1 and v3, because it is the sum of both of them. Therefore, the three vectors are linearly dependent and they cant generate a 3 dimensional vector subspace.

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Use the method of cylindrical shells to find the volume V of the solid obtained by rotating the region bounded by the given curv
harkovskaia [24]

Answer:

Step-by-step explanation:

Let's give this a go here.  The volume formula for the shell method while rotating about a horizontal line is

V=2\pi \int\limits^a_b {p(y)h(y)} \, dy

where p(y) is the distance from the axis of rotation (the x-axis) to the center of the solid.  This is a positive distance and it is just y.

h(y) is the horizontal height of the function.  Our function starts at x = 0 and ends at the function itself, so h(y) = 3 + y^2.

In the shell method when rotating about a horizontal line, we need to use x = y equations, and y-intervals.  Setting up our integral then:

V=2\pi \int\limits^3_2 {y(3+y^2)} \, dy

We can simplify this a bit by distributing the y into the parenthesis:

V=2\pi \int\limits^3_2 {3y+y^3} \, dy

Integrating gives us

V=2\pi|\frac{3y^2}{2}+\frac{y^4}{4}| from 2 to 3

Using the First Fundamental Theorem of Calculus:

V=2\pi[\frac{135}{4}-\frac{40}{4}] which simplifies down to

V=\frac{95\pi}{2}

8 0
3 years ago
Can please cross multiply this for me :)
Alchen [17]
64 x 100 = 6400
11 x x = 11x
I’ll solve this out for you
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4 0
4 years ago
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Keith_Richards [23]
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112 1/2 is fraction form
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4 years ago
5. Calculate the area of the shaded region in the diagram if ABCD is a rectangle. 8 B 4 A 5 3 6 8 D 9 3 C​
il63 [147K]

Answer: 61 unit^2

Step-by-step explanation:

ABCD is a rectangle with dimensions 12 by 11, for a total area of 132 (square units). Although I could determine the lengths of the parallel lines of the interior trapezoid from the data supplied, I'm lazy and decided, instead, to subtract from the total rectangle area the areas of the four right triangles formed outside the shaded area. The area of each triangle is (1/2)b*h, and we are given those dimensions on the figure.

The four triangle areas:

TriD = 36

TriA = 6

TriB = 20

TriC = 9

Total area = 71 square units.

Subtract this from the rectangle's area: 132 - 71 = 61 units^2

This is the area of the shaded trapezoid.

3 0
3 years ago
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Answer:

I think it is A

Step-by-step explanation:

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