Answer:
The circumference of the circle is 52π
Step-by-step explanation:
To solve this exercise we first have to calculate the radius of the circle, for this we will use the formula of area of a circle and we will clear the radius
a = area = 676π
r = radius
a = π * r²
we clear r
r = √(a/π)
now we replace the known values
r = √(676π/π)
r = √(676)
r = 26
now we use the formula to calculate the circumference of a circle
c = π * 2r
c = π * 2 * 26
c = 52π
The circumference of the circle is 52π
Slope intercept form: y = 3/4 x - 7
Point slope form: y + 7 = 3/4 (x+0)
Answer:
1 - F
2 - B
3 - H
4 - A
Step-by-step explanation:
1.
m = -2
b = 4
y < mx + b
y < -2x + 4
F
2.
m = 1
b = -2
y < mx + b
y < 1x -2
y < x - 2
B
3.
m = -4
y <= mx + b
H is the only one that follows those rules
4.
m = 1
y >= mx + b
A is the only one that follows those rules
Answer:
729 * 10^-45
Step-by-step explanation:
Here, we want to expand the value based on the exponent
We have the power multiplying every term in the bracket
That would be;
9^3•10^-45
= 729 * 10^-45
Answer:
7/16
Approximately 0.44
Step by step explanation:
For the 1st student to arrive before 2nd student,
* the probability that he(1st student)to arrive during 3/4 hrs = 3/4
*Then he(1st student) will need to wait for 1/4 hrs
*The probability that he(1st student) arrive during the last 1/4 hrs = 1/4
*Then he(1st student) waits for average of 1/8 hrs (1/4 + 1/4)=1/8
*The total time he(1st student) wait = (3/4 ×1/4) +(1/4× 1/8) = 7/32
*For 1st and 2nd student to meet, the 2nd student need to arrive when 1st student is still arround, therefore the probability that 2nd student arrives when 1st student is arround = 7/32
*If 2nd student arrives before 1st student, the probability that they would meet is 7/32
* Adding both together 7/32 + 7/32 = 7/16
ANSWER = 0.4375
=0.44
