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Elena L [17]
3 years ago
5

A number, n, is added to 15 less than 3 times itself. The result is 101. Which equation can be used to find the value of n? 3n –

15 + n = 101 3n + 15 + n = 101 3n – 15 – n = 101 3n + 15 – n = 101
Mathematics
2 answers:
yawa3891 [41]3 years ago
8 0

Answer:

A : 3n - 15 + n = 101

Step-by-step explanation:

Solution:-

- We will denote a number as "n".

- The result of 3 times itself less 15 would be:

                         3*itself - 15

                         itself = n

                         3*n - 15

- Then a number "n" is added to the above result:

                         3*n - 15 + n.

- The result of above expression is 101:

                         3*n - 15 + n = 101

- Option A is the correct answer

torisob [31]3 years ago
7 0

Answer:

The correct option is;

3·n – 15 + n = 101

Step-by-step explanation:

Here we have,  a question with a word problem

the equation stated is n + (3 × n - 15) = 101

We analyze each of the options to find the correct one as follows;

(a) 3·n – 15 + n = 101

The above equation is equivalent to the equation in the solution above hence it is correct

(b) 3·n + 15 + n = 101

Here 15 is added to 3 times n, therefore it is not correct

(c) 3·n – 15 – n = 101

Here n is subtracted from 3·n - 15 so it is in error

(d) 3·n + 15 – n = 101

Here also n is subtracted while 15 is added so it is not correct.

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y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

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The equation of the perpendicular bisector is y = -x + 11

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