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JulsSmile [24]
3 years ago
8

Please Help me out Thank You

Mathematics
2 answers:
madreJ [45]3 years ago
8 0
Answer: \sqrt{2^4} \cdot \sqrt{5}


Explanation:

\sqrt{80} = \sqrt{2 \times 2 \times 2 \times 2 \times 5} = \sqrt{2^4 \times 5} = \sqrt{2^4} \times \sqrt{5} = \sqrt{2^4} \cdot \sqrt{5}


The Wise Orange knows that "\cdot" means multiply. 
EastWind [94]3 years ago
7 0
\sqrt{2^4} * \sqrt{5}
(the middle choice)
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Burka [1]

Answer:    f'(1)=\dfrac{4}{2y+1}

<u>Step-by-step explanation:</u>

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given:         0 = 2x² - xy - y²

Derivative:  0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

                   y'(2y + 1) = 4x

                   y'=\dfrac{4x}{2y+1}

\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}

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2 years ago
Write a simplified polynomial expression in standard form to represent the area of the rectangle below.
enyata [817]
A = w × l
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2x² + 10x - 4x -20
2x² + 6x - 20
3 0
2 years ago
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What is the nearest hundredth of 2.6666
Advocard [28]

2.66

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5 0
2 years ago
If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumpe
lakkis [162]

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper

Answer: We are given there are 49 cars

Also these 49 cars are in a line stretched 528 feet.

Now the average length of the car is:

Average length = \frac{(length-covered-by-49-cars)}{Number-of-cars}

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Therefore, the average length of car is 10.78 feet

                 

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3 years ago
Helppp me thank youu!<br>BRAINIEST GIVEN!!
dimaraw [331]

Answer:

2?

Step-by-step explanation:

2 is the square root of 4 since 2×2=4

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1 year ago
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