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2 years ago

Solve for the unknown angles. Justify your answers with steps (do not just provide answers)

Mathematics

2 answers:

Cloud [144]2 years ago

7 0

Answer:

PNQ=117

LKQ=102

Step-by-step explanation:

LKQ=180-78=102

KQN=180-67=113

LNQ=360-82-102-113=63

PNQ=180-63=117

AlekseyPX2 years ago

4 0

Answer:

∠ LKQ = 102°, ∠ PNQ = 117°

Step-by-step explanation:

∠ LKQ = 180° - 78° = 102° ( adjacent angles on a straight line )

∠ KQN = 180° - 67° = 113° ( adjacent angles on a straight line )

The sum of the interior angles of a quadrilateral = 360° , then

∠ LNQ = 360° - (102 + 113 + 82)° = 360° - 297° = 63°

Then

∠ PNQ = 180° - 63° = 117° ( adjacent angles on a straight line )

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3 years ago

Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.

Masja [62]

Answer:

See below.

Step-by-step explanation:

So, we have:

$\sec(\theta)=-2/\sqrt{3}$

Recall that secant is simply the reciprocal of cosine. So we can:

$\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2$

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.

Therefore, the possible values for theta is

5π/6 +2nπ

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7π/6 + 2nπ

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