Insert 80 into the equation
1(80) / 5
80/5 = 16
Answer:
x+9
Step-by-step explanation:
f(x) = x, going up 9
that is y=x, going up 9
if you wnat to go up, subtract 9 from y
y -9 = x
y=x+9
convert back to f(x)
f(x) = x+9
Answer:
Step-by-step explanation:
This is a system of equations. The 2 equations are:
4c + 2p = 16
2c + 3p = 12
Let's get rid of the p's first. Do this by multiplying the first equation by -3 and the second equation by 2 to get a new system that looks like this:
-12x - 6p = -48
4c + 6p = 24
Now add to get
-8c = -24 and
c = 3
That means that chocolate is $3 per pound. Now sub that back in to either one of the original equations to get the price for peanuts:
4(3) + 2p = 16 and
12 + 2p = 16 and
2p = 4 so
p = 2
The price for peanuts is $2 per pound.
Question #1 = <span>the amount of snow that falls each hour
question #2 = the starting amount of snow
algebra sucks, keep up the good work
</span>
Answer:
Step-by-step explanation:
Part 1:
Let
Q₁ = Amount of the drug in the body after the first dose.
Q₂ = 250 mg
As we know that after 12 hours about 4% of the drug is still present in the body.
For Q₂,
we get:
Q₂ = 4% of Q₁ + 250
= (0.04 × 250) + 250
= 10 + 250
= 260 mg
Therefore, after the second dose, 260 mg of the drug is present in the body.
Now, for Q₃ :
We get;
Q₃ = 4% of Q2 + 250
= 0.04 × 260 + 250
= 10.4 + 250
= 260.4
For Q₄,
We get;
Q₄ = 4% of Q₃ + 250
= 0.04 × 260.4 + 250
= 10.416 + 250
= 260.416
Part 2:
To find out how large that amount is, we have to find Q₄₀.
Using the similar pattern
for Q₄₀,
We get;
Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹
Taking 250 as common;
Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)
= 2501 − 0.04401 − 0.04
Q₄₀ = 260.4167
Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.
Part 3:
From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.
