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lora16 [44]
2 years ago
12

The equation 2x^2+5kx+k=0, where k is a constant has no real roots. Find possible values of k

Mathematics
1 answer:
frosja888 [35]2 years ago
5 0

Step-by-step explanation:

What do you mean "no real roots" ?

if I understand correctly we have

2x² + 5kx + k = 0

the solutions for such a quadratic equating are

x = (-b ± sqrt(b² - 4ac))/(2a)

a = 2

b = 5k

c = k

so, we get

x = (-5k ± sqrt(25k² - 8k))/4

why would that have no real solutions ?

e.g. k = 2

x = (-10 ± sqrt(100 - 16))/4 = (-10 ± sqrt(84))/4

since the sqrt is a little bit bigger than 9 we get 2 negative solutions for x. but still real.

I don't understand what your need here.

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1. 2 ≤ n ≤ 4

2. 4 * 20

3. T < 80

4. (2 * 4) + (4 * 3)

5. 16 ≤ P ≤ 32

Note: The quantities described are as follows:

1) the allowable number of players on a team  

2) the number of points,  , Han's team earns in one round if every player earns a perfect score  

3) the number of points,  , Han's team earns in one round if no players earn a perfect score  

4) the number of players,  , in a game with six teams of different sizes: two teams have 4 players each and the rest have 3 players each

5) the possible number of players in a game with eight teams

Step-by-step explanation:

1. Let the number of players be n

Since each team can have between 2 and 4 players

n ≥ 2 or 2 ≤ n, and n ≤ 2

Therefore, the allowable number of players on a team   is given by 2 ≤ n ≤ 4

2) There are four players in Han's team and a perfect score is 20

Therefore, the number of points Han's team earns in one round if every player earns a perfect score   is given by 4 * 20

3) There are four players in Han's team

Total score if each player in Han's team earns a perfect score is 4 * 20 = 80

Let the total score of Han's team be T

Therefore, the number of points, Han's team earns in one round if no players earn a perfect score   is given by T < 80

4) If two team have 4 players, it is given by 2 * 4

If the rest four teams have 3 players each, it is given by 4 * 3

Therefore, the number of players in a game with six teams of different sizes: two teams have 4 players each and the rest have 3 players each  is given by (2 * 4) + (4 * 3)

5) Let the possible number of players in a game with be P

Maximum number of players in eight teams = 4 * 8 = 32

Minimum number of players in eight teams = 2 * 8 = 16

P ≤ 32 and P ≥ 16 or 16 ≤P

Therefore, the possible number of players in a game with eight teams  is given by 16 ≤ P ≤ 32

4 0
3 years ago
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