All categories

2 years ago

The equation 2x^2+5kx+k=0, where k is a constant has no real roots. Find possible values of k

Mathematics

1 answer:

frosja888 [35]2 years ago

5 0

Step-by-step explanation:

What do you mean "no real roots" ?

if I understand correctly we have

2x² + 5kx + k = 0

the solutions for such a quadratic equating are

x = (-b ± sqrt(b² - 4ac))/(2a)

a = 2

b = 5k

c = k

so, we get

x = (-5k ± sqrt(25k² - 8k))/4

why would that have no real solutions ?

e.g. k = 2

x = (-10 ± sqrt(100 - 16))/4 = (-10 ± sqrt(84))/4

since the sqrt is a little bit bigger than 9 we get 2 negative solutions for x. but still real.

I don't understand what your need here.

You might be interested in

Please help if you want brianleist (no links please!) Ty!

nikitadnepr [17]

Answer:

The answer is 40 can I please get brainleist

5 0

3 years ago

3x = 0.5.2 x = -6 or x = 0 x = -4 or x = 3 x = -2 or x = 1.5 x = 0 or x = 6

tiny-mole [99]

that is unsolvable coz no double decimal can be used

7 0

2 years ago

108 identical books have a mass of 30 kg. Find

Lynna [10]

Answer:

(i) 540kg

(ii) 5.56 (rounded off to 3 significant figures)

Step-by-step explanation:

$108 \div 30 = 3.6kg$

$(i)3.6 \times 150 = 540kg$

$(ii)3.6 \times x = 20$

$3.6x = 20$

$x = \frac{20}{3.6}$

$x = 5 \frac{5}{9}$

4 0

3 years ago

What is a cubic polynomial function with zeros 3,3 and -3? show your work.

Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

$(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0$

So, cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

4 0

2 years ago

Please help me What does m

Alja [10]

9514 1404 393

Answer:

∠N = 10°

Step-by-step explanation:

Assuming the marked point on segment LN is supposed to be the center of the circle, arc NML is 180°, so arc ML is 180° -160° = 20°.

Arc ML is intercepted by inscribed angle LNM, so the measure of that angle is half the arc measure:

∠N = (1/2)(20°) = 10°

6 0

3 years ago