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3 years ago

13

allison is buying packages of sliced meat for the picnic each package has 20 slicrs of mest 5 are turkey if she buys 80 how many

will be turkey

1 answer:

morpeh [17]3 years ago

7 0

If allison buys 80 packs of meat for the picnic and 5 of those slices in each pack are turkey she would end up with 400 slices of turkey.

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Sofia wrote three numbers between 0.77 and 0.78 what numbers Sofia

Ostrovityanka [42]

Answer:

0.771, 0.772, 0.773

Step-by-step explanation:

three numbers between 0.77 and 0.78

0.77 = 0.770

and

0.78 = 0.780

So,

0.770, 0.771, 0.772, 0.773, 0.780

= 0.77, 0.771, 0.772, 0.773, 0.78

5 0

3 years ago

A sweater is on sale for 30% off the ticketed price of $84. How much will the sweater cost after the discount?

Marianna [84]

84 x .70 = $58.80

Or if you want to do it the long way you can calculate the actual discount (your savings from this purchase first then subtract it from the original price of $84. It`s just easier to figure out what is left (which is 70% of $84).

3 0

3 years ago

Someone help me with this please

disa [49]

Answer:

5

Step-by-step explanation:

with Proportionality

6 0

2 years ago

Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s

notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

No-show rate of 10%.

This means that $p = 0.1$

Four travelers who have made hotel reservations in this study.

This means that $n = 4$

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is $P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523$

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561$

$P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

X = 0 has the highest probability, which means that 0 is the most likely value for X.

7 0

2 years ago

According to a study conducted in one city, 34% of adults in the city have credit card debts of more than$2000. A sample n=300 i

JulsSmile [24]

Answer:

p hat≈N(0.34,0.0273)

Step-by-step explanation:

Given information p=0.34

Number of random samples=300

The sampling distribution of p hat is

p∧≈N(0.34,\sqrt{\frac{0.34(1-0.34)}{300}})

≈N(0.34,0.0273)

4 0

3 years ago