3 by 10kg? ioooooooooooooo
Answer:
Option (1)
Step-by-step explanation:
From the picture attached,
Two planes have been given as plane A and plane B.
Two lines 'm' and 'n' are on the plane A.
These lines intersect each other at a point W.
Therefore, point W describes the point of intersection of the lines 'm' and 'n'.
Option (1) will be the correct option.
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Answer:
3. A=B=70°; C=D=110°
4. A=90°; C=48°
Step-by-step explanation:
Same-side angles of a trapezoid add to 180°.
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3. (2x) +(x+15) = 180
3x + 15 = 180 . . . . simplify
x +5 = 60 . . . . . . . divide by 3
x = 55
A=B=(x+15)° = (55+15)° = 70°
C=D=2x° = 2·55° = 110°
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4. You are given the values of one of the angles on each side, so the other can be found by subtraction:
A=180°-D = 90°
C = 180° -132° = 48°
Answer:
1. y' = 3x² / 4y²
2. y'' = 3x/8y⁵[(4y³ – 3x³)]
Step-by-step explanation:
From the question given above, the following data were obtained:
3x³ – 4y³ = 4
y' =?
y'' =?
1. Determination of y'
To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:
3x³ – 4y³ = 4
Differentiate
9x² – 12y²dy/dx = 0
Rearrange
12y²dy/dx = 9x²
Divide both side by 12y²
dy/dx = 9x² / 12y²
dy/dx = 3x² / 4y²
y' = 3x² / 4y²
2. Determination of y''
To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:
3x² / 4y²
Let:
u = 3x²
v = 4y²
Find u' and v'
u' = 6x
v' = 8ydy/dx
Applying quotient rule
y'' = [vu' – uv'] / v²
y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²
y'' = [24xy² – 24x²ydy/dx] / 16y⁴
Recall:
dy/dx = 3x² / 4y²
y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴
y'' = [24xy² – 18x⁴/y] / 16y⁴
y'' = 1/16y⁴[24xy² – 18x⁴/y]
y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]
y'' = 1/16y⁵[(24xy³ – 18x⁴)]
y'' = 6x/16y⁵[(4y³ – 3x³)]
y'' = 3x/8y⁵[(4y³ – 3x³)]
