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aliina [53]
3 years ago
5

Conditional Probability

Mathematics
1 answer:
trapecia [35]3 years ago
3 0
To solve for P(QIR) we use the formula:
P(QIR)=[P(Q∩R)]/P(R)
But from the diagram:
P(Q∩R)=3/22
P(R)=7/22
hence
P(QIR)=3/22÷7/22=3/7
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Can anyone help with this?
Morgarella [4.7K]

Answer:

111 degrees

Step-by-step explanation:

the total degrees in a hexagon is 720 degrees.

the known angles add up to 379, so there is 341 degrees left.

angle KFE is 105 degrees because it adds up to 180 degrees with GFK.

angle LAD is 130 degrees because it adds up to 180 degrees with BAD.

130+105=230, so there is now 111 degrees left and that is angle x

5 0
3 years ago
Which expression is equivalent to(60)^2-(12)^2?
seraphim [82]

Answer:

The answer is

{60}^{2}  -  {12}^{2}  \\  = (60 - 12)(60 + 12)

Step-by-step explanation:

I am a math teacher If you need any explanation you can communicate with me on Whats on this number +201557831028

3 0
3 years ago
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A sample of 40 people owned an average of 1.35 hats. It is known from a previous study that the population standard deviation of
FrozenT [24]

Answer:

(1,155, 1.545).

Step-by-step explanation:

From Normal distribution tables the z score for 95% CI  = 1.96.

Confidence Interval

= 1.35 +/- 1.96 * 0.63/√40

=  1.35 +/- 0.195

=  (1,155, 1.545).

3 0
3 years ago
James can jog twice as fast as he can walk. He was able to jog the first 9 miles to his grandmother’s house, but then he tired a
dimulka [17.4K]

Answer:

6 mile/hour

Explanation :



Let the speed of walking of James = x mile/hour


speed of jogging = 2x mile/hour


9/2x + 1.5/x = 2


= > (9 + 3)/2x = 2


= > 12 = 4x


= > x = 3


Average speed of walking = 3 mile/hour


Average speed of jogging = 2 * 3 = 6 mile/hour

5 0
3 years ago
The ages of trees in a forest are normally distributed with a mean of 25 years and a standard deviation of 4. Approximately what
harkovskaia [24]

Answer:

78.88%

Step-by-step explanation:

We have been given that

\mu=25,\sigma=4,x_1=20,x_2=30

The z-score formula is given by

z-\text{score}=\frac{x-\mu}{\sigma}

For x_1=20

z_1=\frac{20-25}{4}\\\\z_1=-1.25

For x_2=30

z_2=\frac{30-25}{4}\\\\z_2=1.25

Now, we find the corresponding probability from the standard z score table.

For the z score -1.25, we have the probability 0.1056

For the z score 1.25, we have the probability 0.8944

Therefore, the percent of the trees that are between 20 and 30 years old is given by

0.8944 - 0.1056

= 0.7888

=78.88%

6 0
4 years ago
Read 2 more answers
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