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Romashka-Z-Leto [24]
3 years ago
13

Many cultures around the world still use a simple weapon called a blowgun, a tube with a dart that fits tightly inside. A sharp

breath into the end of the tube launches the dart. When exhaling forcefully, a healthy person can supply air at a gauge pressure of 6.0 kPa.
Required:
What force does this pressure exert on a dart in a 1.5-cm-diameter tube?
Physics
1 answer:
Yuki888 [10]3 years ago
7 0

Answer:

F = 1.06N

Explanation:

In order to calculate the force that produces the given pressure you take into account the following formula:  

P=\frac{F}{A}          (1)

P: pressure = 6.0kPa = 6.0*10³ Pa

F: force = ?

A: cross-sectional area of the tube = π r^2

r: radius of the tube = 1.5cm/2 = 0.75cm = 0.75*10^-2 m

You solve the equation (1) for F, and replace the values for the area A and the pressure P:

F=PA=(6.0*10^{3}Pa)(\pi(0.75*10^{-2}m)^2)\\\\F=1.06N

The force tha produces a pressure of 6.0kPa in a tube with a diameters of 1.5cm is 1.06N

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Anna35 [415]

Answer:

\dot{W_{H} } = 4244.48 Btu/h

Explanation:

Temperature of the house, T_{H} = 70^{0} F

Convert to rankine, T_{H} = 70^{0}+ 460 = 530 R

Heat is extracted at 40°F i.e T_{L} = 40^{0}F  = 40 + 460 = 500 R

Calculate the coefficient of performance of the heat pump, COP

COP = \frac{T_{H} }{T_{H} - T_{L}  } \\COP = \frac{530 }{530 - 500  }\\ COP = \frac{530}{30} \\COP = 17.67

The minimum power required to run the heat pump is given by the formula:

\dot{W_{H} } = \frac{\dot{Q_{H} }}{COP} \\...............(*)

Where the heat losses from the house, \dot{Q_{H} } = 75,000 Btu/h

Substituting these values into * above

\dot{W_{H} } = \frac{75000}{17.67} \\ \dot{W_{H} } = 4244.48 Btu/h

3 0
2 years ago
Levi and Clara are trying to move a very heavy box. Levi is pushing the box with a force of 30 N, and Clara is pulling the box w
mihalych1998 [28]
<span>There is a net force of 15 N allowing Levi and Clara to move the box would be your answer which is B</span>
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A school bus moves at speed of 35 mi/hr for 20 miles. How long will it take the bus to get to school
ludmilkaskok [199]

Answer:

Explanation:

Assuming school is at the end of the 20 mile route, then

20 mi / 35 mi/hr = 0.57142...hr

which is about 34 minutes 17 seconds

6 0
2 years ago
A car moves uphill at 40 km/h and then back downhill at 60 km/h. What is the average speed for the round trip?
jok3333 [9.3K]

Answer:

S_a_v_e_r_a_g_e=48km/h

Explanation:

Ok, the average speed can be calculate with the next equation:

S_a_v_e_r_a_g_e=\frac{Total\hspace{3}distance}{Total\hspace{3}time}   (1)

Basically the car cover the same distance "d" two times, but at different speeds, so:

Total\hspace{3}distance=2*d

and the total time would be the time t1 required to go from A to B plus the time t2 required to go back from B to A:

Total\hspace{3}time=t1+t2

From basic physics we know:

t=\frac{d}{S1}

so:

t1=\frac{d}{S1}

t2=\frac{d}{S2}

Using the previous information in equation (1)

S_a_v_e_r_a_g_e=\frac{2*d}{\frac{d}{S1} +\frac{d}{S2} }=\frac{2*d}{\frac{d*S2+d*S1}{S1+S2} }

Factoring:

S_a_v_e_r_a_g_e=\frac{2*S1*S2}{S1+S2}   (2)

Finally, replacing the data in (2)

S_a_v_e_r_a_g_e=\frac{2*40*60}{60+40} =48km/h

5 0
2 years ago
Two glasses of water have the same thermal energy. must they have the same temperature? explain.
taurus [48]
No,because they  may have more particles 
3 0
2 years ago
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