Work is calculated as the product of Force, Distance, and
angular motion. In this case, the work done by gravity is perpendicular to the motion
of the cart, so θ = 90°
and W=Fdcosθ
W=35.0 N x 20.0 m x cos90
W=0 J
This means that work done perpendicular to the direction of
the motion is always zero.
It is false. We see only a few members of <span>electromagnetic spectrum</span>
Hope it helps!
Answer:
Explanation:
Those five functions are :
1. energy conversion - The conversion of fuel into mechanical energy and dissipation of heat.
2. fluid distribution - the reach of fuel in every necessary part of the machine.
3. fluid control
- the amount of fuel given
4. work performance - maximum output that can be drawn
5. fluid conditioning - the process of confirming the liquid is clean, cool and dry.
Given:
h = 600 m, the height of descent
t = 5 min = 5*60 = 300 s, the time of descent.
Let a = the acceleration of descent., m/s².
Let u = initial velocity of descent, m/s.
Let t = time of descent, s.
The final velocity is v = 0 m/s because the helicopter comes to rest on the ground.
Note that u, v, and a are measured as positive upward.
Then
u + at = v
(u m/s) + (a m/s²)*(t s) = 0
u = - at
u = - 300a (1)
Also,
u*t + (1/2)at² = -h
(um/s)*(t s) + (1/2)(a m/s²)*(t s)² = 600
ut + (1/2)at² = 600 (2)
From (1), obtain
-300a +(1/2)(a)(90000) = -600
44700a = -600
a = - 1.3423 x 10⁻² m/s²
From (1), obtain
u = - 300*(-1.3423 x 10⁻²) = 4.03 m/s
Answer:
The acceleration is 0.0134 m/s² downward.
The initial velocity is 4.0 m/s upward.
Answer:
Yes, if object has moved through a distance, it surely can has zero displacement. as displacement is a vector quantity depending on starting and ending position not on the path.
For example, 1 circle of motion has distance 2πR but 0 displacement.
Explanation:
Yes, zero displacement is possible if an object has moved through a distance.
Suppose a ball starts moving from point A and it returns back at same point A, then the distance will be equal to 20 meters while displacement will be zero.
