Answer:
y = 9.64 m
Explanation:
This exercise should be solved using kinematics in one dimension, let's write the equations for the two cases presented
The rock is released
y = y₀ + V₀₁ t₁ - ½ g t₁²
In this case the speed starts is zero
y = y₀ - ½ g t₁²
The rock is thrown up
y = y₀ + v₀² t₂ -½ g t₂²
The height that reaches the floor is zero
y₀ - ½ g t₁² = y₀ + v₀₂ t₂ - ½ g t₂²
We use the initial velocity with the equation
v₂² = v₀₂² - 2 g y
At the point of maximum height v₂ = 0
v₀₂ = √ (2 g
)
g (-t₁² + t₂²) = 2 √ (2 g
) t₂²
g (- 4.15² + 6.30²) = 2 √ (2 2 g) 6.3
g (22.4675) = 25.2 √ g
g² = 2²5.2 / 22.4675 g
g = 1.12 m / s²
Having the value of g we can use any equation to find the height
y = ½ g t₁²
y = ½ 1.12 4.15²
y = 9.64 m
Schizotypal personality disorder and borderline personality disorder
Answer:
True, check attachment for code
Explanation:
To convert java strings of text to upper or lower case, we can use and inbuilt methods To Uppercase and To lower case.
The first two lines of code will set up a String variable to hold the text "text to change", and then we print it out.
The third line sets of a second String variable called result.
The fourth line is where the conversion is done.
We can compare the string
We can compare one string to another. (When comparing, Java will use the hexadecimal values rather than the letters themselves.) For example, if we wanted to compare the word "Fat" with the word "App" to see which should come first, you can use an inbuilt string method called compareTo.
Check attachment for the code
It depends on speed because it is a part of a car