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Romashka-Z-Leto [24]
3 years ago
13

Many cultures around the world still use a simple weapon called a blowgun, a tube with a dart that fits tightly inside. A sharp

breath into the end of the tube launches the dart. When exhaling forcefully, a healthy person can supply air at a gauge pressure of 6.0 kPa.
Required:
What force does this pressure exert on a dart in a 1.5-cm-diameter tube?
Physics
1 answer:
Yuki888 [10]3 years ago
7 0

Answer:

F = 1.06N

Explanation:

In order to calculate the force that produces the given pressure you take into account the following formula:  

P=\frac{F}{A}          (1)

P: pressure = 6.0kPa = 6.0*10³ Pa

F: force = ?

A: cross-sectional area of the tube = π r^2

r: radius of the tube = 1.5cm/2 = 0.75cm = 0.75*10^-2 m

You solve the equation (1) for F, and replace the values for the area A and the pressure P:

F=PA=(6.0*10^{3}Pa)(\pi(0.75*10^{-2}m)^2)\\\\F=1.06N

The force tha produces a pressure of 6.0kPa in a tube with a diameters of 1.5cm is 1.06N

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I was driving along at 20 m/s , trying to change a CD and not watching where I was going. When I looked up, I found myself 46 m
vampirchik [111]

Answer:

6.46393559312 m/s²

Explanation:

Time taken to cover 56 m

t=\dfrac{56}{29}\ s

Distance covered in 0.42 seconds

0.42\times 20=8.4\ m

From equation of linear motion

s=ut+\frac{1}{2}at^2

8.4+20(\dfrac{56}{29}-0.42)+\dfrac{1}{2}a(\dfrac{56}{29}-0.42)^2=46\\\Rightarrow a=(46-8.4-20(\dfrac{56}{29}-0.42))\times\dfrac{2}{(\dfrac{56}{29}-0.42)^2}\\\Rightarrow a=6.46393559312\ m/s^2

The minimum acceleration is 6.46393559312 m/s²

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3 years ago
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Answer:

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5 0
3 years ago
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The block in the drawing has dimensions L0×2L0×3L0, where L0 =0.5 m. The block has a thermal conductivity of 250 J/(s·m·C˚). In
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3 years ago
Does the efficiency of a motor depend on mass?
Valentin [98]

Practically yes

  • Efficiency=Output/input

So

If mass is more output may come less so it affects the efficiency practically

But thepritically it doesn't

5 0
2 years ago
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The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

5 0
2 years ago
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