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AlekseyPX
2 years ago
8

A cannonball has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction. Drag forces cannot be neglec

ted.
Physics
1 answer:
Novosadov [1.4K]2 years ago
6 0

Answer:

The free-body diagram of the cannonball is found in the attachment below

<em>Note The question is incomplete. The complete question is as follows:</em>

<em>A cannonball has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction. Drag forces cannot be neglected.</em>

<em>Draw the free-body diagram of the cannonball.</em>

Explanation:

Free-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object in a given situation.

In order to construct free-body diagrams, it is important to know the various types of forces acting on the object in that situation. Then, the direction in which each of the forces is acting is determined. Finally the given object is drawn using any given representation, usually a box, and the direction of action of the forces are represented using arrows.

In the given situation of a cannonball which has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction., the forces acting on it are:

F = force exerted by the cannon acting in the direction of angle of projection

Fdrag = drag force. The drag force acts in a direction opposite to the force exerted by the cannon

Fw = weight of the cannonball acting in a downward direction

The free body diagram is as shown in the attachment below.

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008 (part 3 of 4) 3.0 points
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Car A take a time of 2.55hr and car B take a time of 2.14 hr

We know that distance divide by time is speed

here it is given that car A to reach a gas station a distance 189 km from the school traveling at a speed of 74 km/hr​

so speed=distance/time

s=d/t

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1 year ago
The world's fastest production sportscar has a top speed of 415 kmh-1(a)Convert this speed to ms-1.[ 1](b)The distance from Lond
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Answer:

(a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

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Top speed = 415 km/h

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v=415\ km/h

v=415\times\dfrac{5}{18}

v=115.28\ m/s

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d=403\times1609

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d=648.427\ km

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Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{648.427}{415}

t=1.56\ h

t=1\ hours 34\ min

t= 94\ min

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In the time it takes the car to travel from London to Edinburgh,

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Velocity is equal to the displacement divided by time.

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Hence, (a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

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