A) The friction force while the box is stationary is (the coefficient of static friction)*(the normal force). In this case, the normal force is equal to the gravitational force, or the weight. To move the box, we need a minimum horizontal force that is equal to the friction force. The weight is (500 kg)*(9.81 m/s^2)= 4905 N. So, (0.45)*(4905 N) = 2207.25 N.
b) The acceleration will be the horizontal force - the kinetic friction force (since they act in opposite directions) divided by the mass. Kinetic friction force = (coefficient of kinetic friction)*(normal force or weight).
F(net) = (2207.25 N)-(0.30)(4905 N) = 735.75 N
a = (735.75 N)/(500kg)= 1.4715 m/s^2
The first collision because a greater amount of momentum must be taken and used in order to push the cart back, giving it a greater mass and impulse
Answer:
The final pressure will be 6.99 N/m^ 2
Explanation:
Initial volume of tire = 2.00 L
Initial pressure of the tire = 7.00 × 10 5 N/m 2
Initial temperature of tire 31 °C
P1V1 = P2V2
7.00 × 10 5 N/m 2 × V1 = 101325×100 → V1 = 1.45×10^(-5) m^3 = 1.45×10^(-2) L
Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)
pressure of released gas filling the entire 2 L = 2 L/(7.00 × 10^5 N/m^ 2 × 1.45×10^(-5) m^3) = 1.197 ×10^(-4) N/m^2
New pressure = 7.00 × 10^5 N/m^2 - 1.197 ×10^(-4) N/m^2
= 6.99 N/m^ 2
Answer:
Gasoline will float
Asphalt will sink
Cork will float
Explanation:
Simply compare the value of each object's density to that of the sea water (1.025 g/ml). If the density of the object is less than that of the water, the object will float due to the buoyance force.
Contrarily, if the density of the object is larger than that of sea water, the object will sink.
Gasoline, with density 0.66 g/ml which is less than that of sea water, will float.
Gasoline, with density 1.2 g/ml which is more than that of sea water, will sink.
Cork, with density 0.26 g/ml which is less than that of sea water, will float.
To calculate the density of the white dwarf we need the mass of the Sun and the radius of the Earth:
- Sun mass:

- Earth radius:

Assuuming the dwarf to be a perfect sphere, its volume is

.
The average density is given by

so, substituting we find