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Sati [7]
3 years ago
11

A student is throwing a ball. She throws the ball up with her left hand, it passes over her head, and she catches it with her ri

ght hand. The picture shows the path of the ball. The ball is numbered at different positions. What is happening at position 2?
A.Kinetic energy increases as potential energy decreases.
B.Potential energy increases as kinetic energy decreases.

C.Kinetic energy is zero, and the potential energy is greatest.
D.Potential energy and kinetic energy both stay the same.

Physics
1 answer:
pychu [463]3 years ago
8 0

Answer:

(c) at point 2, the ball is at its highest height do its PE is max. Also at ms height, velocity is zero therefore KE is zero.

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A large box has a mass of 500kg and the coefficient of static friction for the box and the floor is 0.45, and the coefficient of
Mumz [18]
A) The friction force while the box is stationary is (the coefficient of static friction)*(the normal force). In this case, the normal force is equal to the gravitational force, or the weight. To move the box, we need a minimum horizontal force that is equal to the friction force. The weight is (500 kg)*(9.81 m/s^2)= 4905 N. So, (0.45)*(4905 N) = 2207.25 N.

b) The acceleration will be the horizontal force - the kinetic friction force (since they act in opposite directions) divided by the mass. Kinetic friction force = (coefficient of kinetic friction)*(normal force or weight). 

F(net) = (2207.25 N)-(0.30)(4905 N) = 735.75 N

a = (735.75 N)/(500kg)= 1.4715 m/s^2
4 0
3 years ago
A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T
Nady [450]
The first collision because a greater amount of momentum must be taken and used in order to push the cart back, giving it a greater mass and impulse
6 0
4 years ago
A bicycle tire contains 2.00 L of gas at an absolute pressure of 7.00 × 10 5 N/m 2 and a temperature of 18.0 °C . What will its
bekas [8.4K]

Answer:

The final pressure will be 6.99 N/m^ 2

Explanation:

Initial volume of tire = 2.00 L

Initial pressure of the tire = 7.00 × 10 5 N/m 2

Initial temperature of tire 31 °C

P1V1 = P2V2

7.00 × 10 5 N/m 2 × V1 = 101325×100 → V1 = 1.45×10^(-5) m^3 = 1.45×10^(-2) L

Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)

pressure of released gas filling the entire 2 L = 2 L/(7.00 × 10^5 N/m^ 2 × 1.45×10^(-5) m^3) = 1.197 ×10^(-4) N/m^2

New pressure = 7.00 × 10^5 N/m^2 - 1.197 ×10^(-4) N/m^2

= 6.99 N/m^ 2

4 0
4 years ago
9. From the densities below, decide whether each substance will sink or float in sea water. Sea water
tekilochka [14]

Answer:

Gasoline will float

Asphalt will sink

Cork will float

Explanation:

Simply compare the value of each object's density to that of the sea water (1.025 g/ml). If the density of the object is less than that of the water, the object will float due to the buoyance force.

Contrarily, if the density of the object is larger than that of sea water, the object will sink.

Gasoline, with density 0.66 g/ml which is less than that of sea water, will float.

Gasoline, with density 1.2 g/ml which is more than that of sea water, will sink.

Cork, with density 0.26 g/ml which is less than that of sea water, will float.

8 0
3 years ago
Read 2 more answers
After the sun exhausts its nuclear fuel, its ultimate fate may be to collapse to a white dwarf state. in this state, it would ha
fenix001 [56]
To calculate the density of the white dwarf we need the mass of the Sun and the radius of the Earth:
- Sun mass: M=1.99 \cdot 10^{30}kg
- Earth radius: r=6.37 \cdot 10^6 m
Assuuming the dwarf to be a perfect sphere, its volume is V= \frac{4}{3} \pi r^3.
The average density is given by
d= \frac{M}{V}
so, substituting we find
d= \frac{M}{ \frac{4}{3}\pi r^3 }=1.83 \cdot 10^9 kg/m^3
8 0
3 years ago
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