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alexgriva [62]
4 years ago
13

Quantities must have different units before they can be added or subtracted.

Physics
1 answer:
AVprozaik [17]4 years ago
7 0
<span>The statement, Quantities must have different units before they can be added or subtracted, is false. <span>You need to note when you add or subtract units, they must be first homogenous or the same. In conversion factors, always check for the units. Suppose that you are given the area of a certain house which is 164m2. You are asked to find it in square feet. You will need to multiply 0.305m by itself to get m2. You have (0.305m)^2 is equal to 0.093025ft2. Now you have an equivalent factor of 1ft2 is equal to 0.093025ft2. After that, divide 164m2 by 0.093025ft2 and you will get 1762.97ft2. </span></span>
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Explanation:

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3 years ago
2. A box filled with books has a mass of 15.0 kg. It is pushed across the floor with a constant force of 60.0 N. If the friction
sesenic [268]

Answer:

3 m/s^{2}

Explanation:

ΣF=ma

The two forces at play are the force applied and the force due to friction. As they are opposing forces set the direction being pushed as the positive in the x direction. the equation you come out with is 60 - 15=(15)A (we know mass to be 15kg). Solve for 3 m/s^2.

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3 years ago
What frequency is received by a stationary mouse just before being dispatched by a hawk flying at it at 24.7 m/s and emitting a
Montano1993 [528]

Answer:

   f' = 3665.51 Hz

Explanation:

given,

speed of the hawk = 24.7 m/s

frequency of screech emitted by the hawk = 3400 Hz

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By Doppler's effect

f' = (\dfrac{v}{v-v_s}})f

f' is the frequency received by the mouse

v is the speed of the sound

v_s is the speed of the hawk

now,

f' = \dfrac{341}{341-24.7}}\times 3400

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The frequency received by the stationary mouse is equal to 3665.51 Hz

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3 years ago
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