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Strike441 [17]
3 years ago
15

What is the resistivity of a wire of 1.3 mm diameter, 2.3 m length, and 61 ms resistance. Number Units The number of significant

digits is set to 2; the tolerance is +/-2%
Physics
1 answer:
kakasveta [241]3 years ago
3 0

Answer:

\rho = 3.68 *10^{-8} Ω. m

Explanation:

The resistance is given as

R = \frac{\rho L}{A}

Where A IS Cross sectional area of wire= \pi r^{2}

therefore resistivity \rho can be wrtten as

\rho = \frac{\pi Rd^{2}}{4L}

Putting all value to get resistivity value\rho =\frac{\pi* 61*10^{-3}* (1.33*10^{-3})^{2}}{4*2.3}

\rho = 3.68 *10^{-8} Ω. m

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A 2430 pound roller coaster starts from rest and is launched such that it crests a 105 ft high hill with a speed of 59 mph. The
Rudik [331]

Answer:

Explanation:

Given

Weight of roller coaster is W=2430\ pound

mass of roller coaster m=\frac{W}{g}=\frac{2430}{32.2}=75.45

Distance traveled by roller coaster d=396\ ft

drag force f_d=85\ pounds

velocity at top v=59 mph\approx 86.53\ ft/s

Suppose E is the initial energy

Conserving Energy at bottom and top

E=\frac{1}{2}mv^2+mgh+f_d\cdot d

E=0.5\times 75.45\times 86.53^2+2430\times 105+85\times 396

E=2.9\times 10^5\ foot-pound

5 0
3 years ago
Some compounds, like carbon dioxide, are gaseous at room temperature, while others are solid at room temperature. Why is this?
Vesnalui [34]
The answer of a & b are force of cohesion and force of adhesion
Of rest two answers I don't know 
8 0
3 years ago
Read 2 more answers
A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness
Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

\sigma_h = \frac{Pd}{2t}

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

\sigma_l = \frac{Pd}{4t}

The letters have the same meaning as before.

Then he hoop stress would be,

\sigma_h = \frac{Pd}{2t}

\sigma_h = \frac{75 \times 8}{2\times 0.25}

\sigma_h = 1200psi

And the longitudinal stress would be

\sigma_l = \frac{Pd}{4t}

\sigma_l = \frac{75\times 8}{4\times 0.25}

\sigma_l = 600Psi

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

\tau_{max} = \frac{\sigma_h}{2}

\tau_{max} = \frac{1200}{2}

\tau_{max} = 600Psi

Therefore the maximum shear stress in the pressure vessel when it is subjected to this pressure is 600Psi

6 0
3 years ago
The tendency of an object to resist a change in its motion is called
Nikolay [14]

Answer:

inertia

Explanation:

4 0
2 years ago
A jet travels at 489 meters per second how long does it take to travel 235 m? answer in seconds
Sladkaya [172]

if in 1 second the jet goes 428 meters and you want to know how long it takes to go 237 meters you just divide 237/428  

it can be written like this  

_1_ = __x__  

428 237  

cross multiply  

428 times x = 1 times 237  

428x=237  

divide by 428 on both sides  

x= 237/428  

x=0.5537 seconds

7 0
3 years ago
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