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geniusboy [140]
3 years ago
6

What discovery by galileo supported the helicentric (sun centered) model of our solar system?

Physics
1 answer:
spayn [35]3 years ago
4 0
Firstly the telescope helped with this discovery, in that he saw rings of Saturn and of Jupiter, which has moons orbiting around it as well as shadows of the moon and Mars and took very detailed notes on them seeing that shadows moved across the moon as seasons changing.
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When would a negative value for distance make sense?( think about velocity)
inn [45]

Answer:

An object which moves in the negative direction has a negative velocity. If the object is speeding up then its acceleration vector is directed in the same direction as its motion (in this case, a negative acceleration).

Explanation:

3 0
3 years ago
23. The force required to accelerate a 2.0-kilogram
Marianna [84]
Answer:
C) 8.0 N

Explanation:
F=m*a
4 0
3 years ago
What instrument is normally used to measure atmospheric pressure?
Anuta_ua [19.1K]
B. Barometer is used to measure atmospheric pressure.
6 0
3 years ago
Two vectors A and B have components (0,1) and (-1,3), respectively. What is magnitude of the sum of these two vectors?
AnnZ [28]
We first add the x and y components of the vector to get the x and y components of the resultant vector:
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-1 , 4
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4 0
3 years ago
Ajani is trying to experimentally measure Planck's constant h. He does this by shining different wavelengths of monochro- matic
olga_2 [115]

Answer:

h = 1.01 x 10⁻³⁴ J.s

Explanation:

The energy applied by the voltage must be equal to the energy associated with the wavelength of light:

eV = \frac{hc}{\lambda}\\

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = stopping potential

h = Planck's Constant = ?

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light

For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:

(1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\

h = 1.49 x 10⁻³⁴ J.s

For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:

(1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\

h = 0.53 x 10⁻³⁴ J.s

Taking average of both values:

h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}

<u>h = 1.01 x 10⁻³⁴ J.s</u>

3 0
3 years ago
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