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faust18 [17]
3 years ago
15

Please help meeeee!!!!!!

Physics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

Net force

Explanation:

Bruh, easy question

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Someone please help me for a brainliest but it has to be correct
Katarina [22]
The answer is 34 you have to add the numbers and divide them by how many numbers there are
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3 years ago
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How many revolutions per minute would a 20 m -diameter ferris wheel need to make for the passengers to feel "weightless" at the
timurjin [86]
The general equation for the forces acting on the passengers at the topmost point of the ferris wheel is
mg - R = m \omega^2 r
where
mg is the weight of the passengers
R is the normal reaction of the cabin
m \omega^2 r is the centripetal force

In order to feel weightless, the normal reaction felt by the passengers should be zero. Therefore, the equation becomes:
mg=m \omega^2 r
or
g=\omega^2 r
where \omega is the angular frequency of the wheel and r is its radius. Since we know its radius, 
r= \frac{20 m}{2}=10 m
we can calculate the angular frequency:
\omega= \sqrt{ \frac{g}{r} } = \sqrt{ \frac{9.81 m/s^2}{10 m} } =0.99 rad/s
From which we find the frequency at which the ferris wheel should rotate:
f= \frac{\omega}{2 \pi}= \frac{0.99 rad/s}{2 \pi}=0.158 s^{-1}
This is the number of revolutions per second, so the number of revolutions per minute will be
f=0.158 s^{-1} \cdot 60 = 9.48 min^{-1}
6 0
3 years ago
A roller coaster car is traveling on a track without any friction or added energy. The people, car, and track of the roller coas
Harlamova29_29 [7]

Answer:

This might not be right but i think it is "Speedway Coasters, Inc., reserves the right to exact a $50.00 fine"

Explanation:

3 0
4 years ago
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Calcular el módulo del vector resultante de dos vectores fuerza de 9 [N] y 12 [N] concurrentes en un punto o, cuyas direcciones
sdas [7]

Answer:

a) 20.29N

b) 19.43N

c) 15N

Explanation:

To find the magnitude of the resultant vectors you first calculate the components of the vector for the angle in between them, next, you sum the x and y component, and finally, you calculate the magnitude.

In all these calculations you can asume that one of the vectors coincides with the x-axis.

a)

F_R=(9cos(30\°)+12)\hat{i}+(9sin(30\°))\hat{j}\\\\F_R=(19.79N)\hat{i}+(4.5N)\hat{j}\\\\|F_R|=\sqrt{(19.79N)^2+(4.5N)^2}=20.29N

b)

F_R=(9cos(45\°)+12)\hat{i}+(9sin(45\°))\hat{j}\\\\F_R=(18.36N)\hat{i}+(6.36N)\hat{j}\\\\|F_R|=\sqrt{(18.36N)^2+(6.36N)^2}=19.43N

c)

F_R=(9cos(90\°)+12)\hat{i}+(9sin(90\°))\hat{j}\\\\F_R=(12N)\hat{i}+(9N)\hat{j}\\\\|F_R|=\sqrt{(12N)^2+(9N)^2}=15N

7 0
3 years ago
A spider can tell when its web has captured, say, a fly because the fly's thrashing causes the web threads to oscillate. A spide
Aleonysh [2.5K]

Answer:

Ratio of oscillation frequency is 1.41

Explanation:

Given

m2=2.00m

m1=m

The angular frequency is given as

w=\sqrt{\frac{K}{m} }\\ where \\T=2\pi \sqrt{\frac{m}{K} }

For two different masses m1 and m2

\frac{w_{1} }{w_{2}}=\sqrt{\frac{(\frac{K}{m1} )}{(\frac{K}{m2} )} }\\\frac{w_{1} }{w_{2}}=\sqrt{\frac{m2}{m1} }\\   \frac{w_{1} }{w_{2}}=\sqrt{2}\\ so\\ratio=1.41

5 0
3 years ago
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