1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlekseyPX
3 years ago
5

You just got a new job with the Biden Administration as a House Clerk working full time (40 hours a week) with

Mathematics
1 answer:
avanturin [10]3 years ago
3 0

Answer:

No

Step-by-step explanation:

You are making alot of money but you can't pay off all of this and still have money left over

You might be interested in
A function has cheating x's.<br> True<br> False
Assoli18 [71]
True
Hope this helps
Have a wonderful day or night
8 0
2 years ago
To complete bookshelves, a customer at your store needs to purchase vertical brackets to attach to the wall. The customer wants
stiks02 [169]
We are given with
height = 9 feet
length = 10 feet
wall brackets:
48-in costing $12.95
60-in costing $16.95
distance of brackets from ends = 1 foot
maximum distance between brackets= 24 inches

The brackets are
48/12 = 4 feet
and
60/12 = 5 feet

One of each must be used to cover the height of the shelf

The length of the shelf is
60 inch
subtracting 1 in from each side for the allowance
60 - 2 = 58 in
Dividing by 24 inches
58/24 = 2.41 ~ 3 

The total cost is
($12.95 + <span>$16.95) * 3 = $89.7
The total cost of the brackets is </span>$89.7
8 0
3 years ago
At a particular music store, CDs are on sale at $12.00 for the first one purchased and $9.00 for each additional disc purchased.
ddd [48]
D. 9 CD's...................
5 0
3 years ago
Read 2 more answers
What are the solutions of 4x2 - 16X = 16x - 39
Alex17521 [72]

Answer:

x = \frac{3}{2}, x = \frac{13}{2}

Step-by-step explanation:

Given

4x² - 16x = 16x - 39 ( subtract 16x - 39 from both sides )

4x² - 32x + 39 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term, that is

product = 4 × 39 = 156 and sum = - 32

The factors are - 26 and - 6

Use these factors to split the x- term

4x² - 26x - 6x + 39 = 0 ( factor the first/second and third/fourth terms )

2x(2x - 13) - 3(2x - 13) = 0 ← factor out (2x - 13) from each term

(2x - 13)(2x - 3) = 0

Equate each factor to zero and solve for x

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

2x - 13 = 0 ⇒ 2x = 13 ⇒ x = \frac{13}{2}

4 0
3 years ago
X^2=6x+1
Genrish500 [490]

Answer:

x=+-√10+3

Step-by-step explanation:

x^2=6x+1

x^2-6x=1

To create a trinomial square on the left side of the equation, find a value that is

equal to the square of half of b

a is the number next to x^2

b is the number next to x

c is the last number

b is -6

half of b is -3

square of half of b is 9

put 9 on both sides of the = sign

x^2-6x+9=1+9

x^2-6x+9=10

(x-3)^2=10

take the square root of both sides of the = sign

√(x-3)^2=√10

x-3=√10

x=+-√10+3

8 0
2 years ago
Other questions:
  • For the problem 135/5, draw two different ways to break apart the array. Use the Distributive property to write products for eac
    8·1 answer
  • A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection ac
    9·2 answers
  • Kal is decorating the outside edge of a square
    14·1 answer
  • Solve the equation.
    11·1 answer
  • 30 + 6p = 7 (p+ 6 ) -5<br> Please answer
    15·2 answers
  • If ​P(E)=0.55​, ​P(E or ​F)=0.65​, and​ P(E and ​F)=0.20​, find​ P(F).
    8·1 answer
  • PLZZZZZZZZ HELPPPPPPPP!!!!
    6·1 answer
  • What is the equation of the line slope-intercept form?​
    12·1 answer
  • Shawna reduced the size of a rectangle to a height of 2 in. What is the new width if it was originally 24 in wide and 12 in tall
    14·2 answers
  • The cumulative distribution function f(x) of a discrete random variable x is given by f(0) =. 30, f(1) =. 70, f(2) =. 90 and f(3
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!