C + (4 - 3c) - 2 = 0

2 answers:

4 0

C + (4 - 3c) - 2 = 0
c + 4 - 3c - 2 = 0
c - 3c + 4 - 2 = 0
 -2c + 2 = 0
 - 2 - 2
 -2c = -2
 -2 -2
 c = 1

finlep [7]3 years ago

3 0

C+(4−3c)−2=0

simplify step-by-step.

c+4−3c−2=0

c+4+−3c+−2=0

(c+−3c)+(4+−2)=0(Combine Like Terms)

−2c+2=0

−2c+2=0

Subtract 2 from both sides.

−2c+2−2=0−2

−2c=−2

Divide both sides by -2.

−2c/−2 = −2/−2

c=1

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