Answer:
option number 2
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Answer:
1
Step-by-step explanation:
None of the sides are equal. Isosceles means that 2 sides are equal. Equilateral means that all sides are equal.
You can sort them on the shapes that are the same or different
Let the total cost of the item be represented by C and the price be represented by P, then given that t<span>he total cost of an item including sales tax is directly proportional to its price, thus</span>

where k is a constant.
Given that <span>the total cost of a $32 item is $33.60, thus

Therefore, the total cost on a $55 item is given by

</span>
Answer:

Step-by-step explanation:
We have been an integral
. We are asked to find the general solution for the given indefinite integral.
We can rewrite our given integral as:


Now, we will apply the sum rule of integrals as:


Using common integral
, we will get:

Now, we will use power rule of integrals as:




We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

Therefore, our required integral would be
.