You can find the slope of a linear function by taking two points and finding the change in y over change in x.
Hm, but the values you gave for the tables don't make sense for a linear function/relationship. But let's just pick two points as an example.
So two points you can pick are (-2, 13) and (1, -3).
The slope, change in y over change in x is in other words (y2 - y1 / x2 - x1), where (x1, y1) is one point and (x2, y2) is another.
(-3 - 13) / (1 - -2) = -16/3 = -(16/3)
Or you could have switched up the order of those coordinates but you still get the same answer.
(13 - -3) / (-2 - 1) = 16 / (-3) = -(16/3)
B. Would be your answer
Using synthetic division, it would turn out to be x+9-9/x+8
Hope I helped!
Given:
In ΔJKL, m∠L=90°, JL = 80, KJ = 89, and LK = 39.
To find:
The value of sine of ∠J.
Solution:
In a right angle triangle,
In triangle JKL,
Therefore, the value of sine of ∠J is about 0.44.
Answer:
12
Step-by-step explanation:
the ruler measured 12
The slope is -1/2. I know this because slope intercept of a line is y = mx + b. In the equation, y = -1/2 + 1/4, the slope is -1/2 and the y intercept is 1/4.
m stands for slope
b stands for y intercept
