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umka21 [38]
3 years ago
6

If your little sister watches you and tries to copy everything you do, she is exhibiting which type of learning? classical condi

tioning insightful learning social learning habituation
Mathematics
2 answers:
tankabanditka [31]3 years ago
7 0

Answer:

The answer is social learning.

Step-by-step explanation:

If your little sister watches you and tries to copy everything you do, she is exhibiting which type of learning?

Here, the little sister is exhibiting social learning.

Social learning theory is defined as the view, that people learn by observing others.

Snezhnost [94]3 years ago
5 0
Insightful learning

Also how does this drop down in mathematics?
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ladessa [460]

Answer:

Why

Step-by-step explanation:

Did you report my answer ?

Did u notice u lost 40 points so then u tricked me into answering it for free ?

4 0
3 years ago
Hi everyone I need to do this assignment for geometry and I have been stuck on it for days, the question is: "On a piece of pape
borishaifa [10]
Example in the attachment below.

8 0
3 years ago
Find the slope of (6,-2) and (-3,1)
My name is Ann [436]

Answer:

m=1/3

Step-by-step explanation:

so find slope do this

(y^2-y^1)/(x^2-x^1)

so

(1+2)/(-3-6)

1/3

7 0
3 years ago
Solve for line segment AB
Molodets [167]

Answer:

AB = 32

Step-by-step explanation:

Given:

AD = 40

CD = 9

Required:

Find the length of segment AB

Solution:

BC and CD are radius of the circle. Therefore,

BC = CD = 9

AB = AC - BC

AB = AC - 9

We need to find AC

Since AD is tangent, CD is perpendicular to AD, this means that <D is a right angle. This makes ∆ADC a right triangle.

Therefore, we can apply Pythagorean theorem to find AC.

Thus:

AC² = AD² + CD²

AC² = 40² + 9²

AC² = 1,681

AC = √1,681

AC = 41

Let's find BC:

AB = AC - 9

Plug in the value of AC

AB = 41 - 9

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5 0
3 years ago
Below are the first six terms of a sequence: a1 = 8 a2 = 22 a3 = 50 a4 = 106 a5 = 218 a6 = 442 Fill in the appropriate constant
Phoenix [80]

Check the forward differences of the sequence:

22 - 8 = 14

50 - 22 = 28 = 2*14

106 - 50 = 56 = 4*14

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442 - 218 = 224 = 16*14

The differences are the products of increasing powers of 2 and 14:

a_2-a_1=14\cdot2^0

a_3-a_2=14\cdot2^1

a_4-a_3=14\cdot2^2

and so on, with

a_n-a_{n-1}=14\cdot2^{n-2}

\implies a_n=a_{n-1}+7\cdot2^{n-1}

Then the sequence has the recursive definition,

\boxed{\begin{cases}a_1=8\\a_n=a_{n-1}+7\cdot2^{n-1}&\text{for }n>1\end{cases}}

5 0
3 years ago
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