Answer:
vertex: (1, -49)
x-intercepts: (-6, 0) and (8, 0)
Step-by-step explanation:
I graphed it and looked for the needed information
here's the graph if you want it:
a. There are four 5s that can be drawn, and
ways of drawing any three of them. There are
ways of drawing any three cards from the deck. So the probability of drawing three 5s is

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of
of getting drawn.
b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability
of being drawn.
c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of
.
- - -
Note:
is the binomial coefficient,

Answer:
4
Step-by-step explanation:
Proportionality between skein values
8:2=4:1
Proportionality between cost values
28:7=4:1
The variation(both the skein values and cost values) has the constant of 4 ie the 1st skein value × 4= the last skein value & the 1st cost value × 4=the last cost value
Answer:
Answer is 116
Step-by-step explanation:
12(10)-4 is 116