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Elodia [21]
3 years ago
13

How many kilometers are in 2 meters and in 13 meters

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0

there  Are 2000 Kilometers in 2 meter

There Are 13000 Kilometers in 13 meters


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The formula V=Bh, where B represents the area of the base, can be used to find the volume of a cylinder. Which formula is equiva
Karo-lina-s [1.5K]

Answer:

C

Explanation:

B=Base Area

In a cylinder, the base area is a circle.

Area Circle=pi r^2

Replace base area with area of circle:

V=pi r^2 H

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3 years ago
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1. The Alabama state flag is white and has two diagonal red stripes. If the m<1 = 135°, what is
MaRussiya [10]

Using the supplementary angles theorem, it is found that the measure of the second angle is of m<2 = 45º.

<h3>What are supplementary angles?</h3>

Two angles are supplementary when the <u>sum of their measures is of 180º</u>.

The Alabama state flag has <u>two lines opposite by the same vertex</u>, hence two angles that are sided are supplementary, hence:

m<1 + m<2 = 180º.

135º + m<2 = 180º.

m<2 = 45º.

The measure of the second angle is of m<2 = 45º.

More can be learned about supplementary angles at brainly.com/question/12919120

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8 0
2 years ago
select the correct answer. Consider the function f. Which statement is true about function f? NO LINKS!! ​
andre [41]

Answer:

C) As x approaches positive infinity, f(x) approaches positive infinity

Step-by-step explanation:

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  • This implies that there are asymptotes at x=0 and x=2.
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2 years ago
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kati45 [8]

Answer: The answer is C = -P + R

3 0
1 year ago
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What are the coordinates of the point on the directed line segment from (-6, -3) to
melamori03 [73]

Given:

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.

To find:

The coordinates of that point.

Solution:

Section formula: If point divides a line segment in m:n, then the coordinates of that point are

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5. Using section formula, we get

Point=\left(\dfrac{6(5)+5(-6)}{6+5},\dfrac{6(8)+5(-3)}{6+5}\right)

Point=\left(\dfrac{30-30}{11},\dfrac{48-15}{11}\right)

Point=\left(\dfrac{0}{11},\dfrac{33}{11}\right)

Point=\left(0,3\right)

Therefore, the coordinates of the required point are (0,3).

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3 years ago
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