Calculate the z-score for the given data points in the item using the equation,
z-score = (x - μ) / σ
where x is the data point, μ is the mean, and σ is the standard deviation.
Substituting,
(47.7) z-score = (47.7 - 52.5)/2.4 = -2
This translates to a percentile of 2.28%.
(54.9) z-score = (54.9 - 52.5)/2.4 = 1
This translates to a percentile of 84.13%.
Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em>
Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs.
Slope-intercept form:
y=mx+b
m=slope
b=y-intercept
We have this line: y=9x+3; a line parallel to this line (y=9x+3) will have the same slope; therefore m would be equal to 9 (m=9).
Data:
m=9
b=-2
y=mx+b
y=9x-2
Answer: y=9x-2
Answer: It should be the third one
Step-by-step explanation:
Answer:
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Step-by-step explanation:
Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.
Let five years ago be group I X and as of now be group II Y
(Two tailed test at 5% level of significance)
Group I Group II combined p
n 270 300 570
favor 120 140 260
p 0.4444 0.4667 0.4561
Std error for differene =
p difference = -0.0223
Z statistic = p diff/std error = -1.066
p value =0.2864
Since p value >0.05, we accept null hypothesis.
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
These three angles are on a line so must total 180°.
So 180-(52+58)=
180-110=70
So angle q is 70°.