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3 years ago

Given a polynomial f(x), if (x - 2) is a factor, what else must be true?

2 answers:

7 0

If a number is a root of a polynomial, then we substitute the number to x of the polynomial, the answer or y is equal to zero. Hence, in this situation, if (x - 2) is a factor, the root is equal to 2. This means then that upon substituting 2 to the function, y is equal to zero. Answer then is A. f(2) = 0

PSYCHO15rus [73]3 years ago

5 0

Answer:

f(2)=0

Step-by-step explanation:

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A pet store sells angle fish for $6 each and clown fish for $4 each. If the pet store sold fish for $36, how many of each type d

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There are four possibilities...but first does the problem tell you how many total fish were sold?

If not the possible combinations are:

0 angel and 9 clownfish
2 angel and 6 clownfish
4 angel and 3 clownfish
6 angel and 0 clownfish

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3 years ago

If Megan sells 22 cakes, then f(22) = 121?

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3 years ago

Oil is leaking out of a ruptured tanker at the rate of r(t)=30e^(?0.09t) thousand liters per minute.

zmey [24]

Answer:

At t = 0, oil is leaking out of a ruptured tanker at the rate of 30 thousand liters per minute.

At t = 60, oil is leaking out of a ruptured tanker at the rate of 0.1355 thousand liters per minute.

331.82 thousands of liters leak out during the first hour.

Step-by-step explanation:

The oil leakage rate, in thousand liters per minute, is:

$r(t) = 30e^{-0.09t}$

A. At what rate, in thousands of liters per minute, is the oil leaking out

At t = 0:

This is r(0)

$r(t) = 30e^{-0.09t}$

$r(0) = 30e^{-0.09*0} = 30$

At t = 0, oil is leaking out of a ruptured tanker at the rate of 30 thousand liters per minute.

At t = 60:

This is r(60)

$r(t) = 30e^{-0.09t}$

$r(60) = 30e^{-0.09*60} = 0.1355$

At t = 60, oil is leaking out of a ruptured tanker at the rate of 0.1355 thousand liters per minute.

B. How many thousands of liters leak out during the first hour?

r(t) is in thousand liters per minute.

Each hour has 60 minutes.

So the answer to this question is the integral from 0 to 60 of r(t).

Integral of the exponential function

$\int {e^{at}} \, dt = \frac{e^{at}}{a}$

$\int\limits^{60}_0 {r(t)} \, dt$

$\int\limits^{60}_0 {30e^{-0.09t}} \, dt$

$-333.33e^{-0.09t}$ , from t = 0 to t = 60.

This is

$-333.33e^{-0.09*60} - (-333.33e^{-0.09*0}) = 331.82$

331.82 thousands of liters leak out during the first hour.

6 0

4 years ago

Tina pet sits to earn extra money. She charges a flat service fee of $20, plus $20 per day. If one of her customers spent less t

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3 years ago

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D 1small bag 5 large bags
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3 years ago