Answer:
57.14 % ≈ 57 %
Explanation:
First step is to find the molar mass of the compound. This is done by adding the atomic masses of the elements present.
The atomic masses of the elements are given below;
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O = 16.00 g/mol
NaHCO3 = (1 mol * Na) + (1 mol * H) + ( 1 mol * C) + (3 mol * O)
NaHCO3 = (1 * 22.99) + (1 * 1.01) + (1 * 12.01) + (3 * 16)
NaHCO3 = 22.99 + 1.01 + 12.01 + 48
NaHCO3 = 84.01g
Formular for percentage composition;
Percentage composition = (Mass of element / Mass of Compound) * 100
Percentage composition = (48 / 84.01) * 100
Percentage composition = 57.14 %
Rounding up to the nearest whole number = 57 %