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olga nikolaevna [1]
3 years ago
14

Ways of preventing rusting​

Chemistry
2 answers:
Flura [38]3 years ago
5 0

Answer:

Here is your answer......

lesya [120]3 years ago
4 0
Use an Alloy. Many outdoor structures, like this bridge, are made from COR-TEN steel to reduce the effects of rust. ...
Apply Oil. ...
Apply a Dry Coating. ...
Paint the Metal. ...
Store Properly. ...
Galvanize. ...
Blueing. ...
Powder Coating.
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A neutral solution has a(n) _______ amount of hydroxide ions compared to hydrogen ions.
erastovalidia [21]
The answer is 'equal'. Hydroxide ions are OH- and Hydrogen ions are H+. Have you noticed they're opposite charges? Positive + negative = neutral. That's all there is to it :)
4 0
3 years ago
Explain what would happen if an electron and a proton were brought near each other and then released. why would this happen?
Leni [432]
They would repel one another because they they have opposing charges
3 0
4 years ago
(GIVING BRAINLIEST) do what the following image says.
S_A_V [24]

Answer:

hope it helps.

<h3>stay safe healthy and happy.<u>.</u><u>.</u></h3>

7 0
3 years ago
Read 2 more answers
The base that will NOT combine with 2-deoxyribose to form a nucleic acid is _____.
beks73 [17]

Answer:

Uracil

Explanation:

The base that will NOT combine with 2-deoxyribose to form a nucleic acid is Uracil.

2-deoxyribose is a pentose sugar found in the DNA (Deoxyribonucleic acid). It is devoid of oxygen in its 2' position. The bases found in DNA are Adenine, Guanine, Cytosine and Thymine. Adenine, Guanine, and Cytosine are also found in RNA (Ribonucleic acid). Thymine is not present in RNA, it is only found in DNA. The base found in RNA is Uracil which in turn is not present in DNA. The five carbon sugar present in RNA is ribose which combines with Uracil.

3 0
3 years ago
The radioactive decay of a certain sample produced 846 disintegrations per minute. exactly 3.00 days later, the rate of decay wa
Margarita [4]

Answer:

\boxed{\text{1.81 da}}

Explanation:

1. Calculate the decay constant

The integrated rate law for radioactive decay is 1

\ln\dfrac{A_{0}}{A_{t}} = kt

where

A₀ and A_t are the counts at t = 0 and t

k is the radioactive decay constant

\ln \dfrac{846}{269} = k \times 3.00\\\\\ln3.145 = 3.00k\\1.146 = 3.00k\\\\k =\dfrac{1.146}{3}\\\\k = \text{0.382 /da}\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{0.382} = \text{1.81 da}

The half-life for decay is \boxed{\textbf{1.81 da}}.

3 0
4 years ago
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