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xxTIMURxx [149]
3 years ago
9

A company has a policy making the compensation of its CEO proportional to the dividends that are paid to shareholders. If the di

vidends increase from $72 to $80 and the CEO’s compensation is increased from $360,000 to $420,000, was the company’s policy followed?
Mathematics
1 answer:
Serggg [28]3 years ago
3 0
Well... looking at proportions, we're being asked \bf \cfrac{72}{360000}=\cfrac{80}{420000}\impliedby \textit{are those proportions the same?}
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Determine whether the function f(x)= 1/x^2 is even, odd or neither.
gulaghasi [49]

The function f(x)= 1/x^2 is even. Hope that helps!

4 0
3 years ago
Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.
AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= \frac{2}{3} -\frac{1}{3} i\sqrt{26}

x₂ = \frac{2}{3} +\frac{1}{3} i\sqrt{26}

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

  1. <u>If the discriminant is zero</u>, the equation will have only one solution and it will be real
  2. <u>If the discriminant is greater than zero</u>, then the equation will have two solutions and they both will be real.
  3. <u>If the discriminant is less than zero,</u> then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104

Therefore our discriminant is less than zero and we know<u> that our equation will have two solutions in the complex numbers. </u>

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = \frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂=\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}

These are our two solutions in the imaginary numbers.

7 0
3 years ago
What two numbers add to be 6 and multiply to be 15
yarga [219]
   
\displaystyle \bf \\&#10;x_1+x_2=6\\\\&#10;x_1\cdot x_2=15\\\\&#10;\Longrightarrow~~x^2-6x+15=0\\\\&#10;x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-60}}{2}=\\\\&#10;=\frac{6\pm\sqrt{-24}}{2}=\frac{6\pm2\sqrt{-6} }{2}=3\pm i\sqrt{6}\\\\&#10;x_1=\boxed{3-i\sqrt{6}}\\\\&#10;x_2=\boxed{3+i\sqrt{6}}\\\\&#10;\texttt{Verify:}\\\\&#10;x_1+x_2=3-\underline{i\sqrt{6}}+3+\underline{i\sqrt{6}}=3+3=6~~correct\\\\&#10;x_1\cdot x_2=(3-i\sqrt{6})(3+i\sqrt{6})=3^2-(i\sqrt{6})^2=9+6=15~~correct



4 0
4 years ago
A park charges $19 for one round of miniature golf and a reduced fee for each additional round played. If Tom paid $34 for 6 rou
iragen [17]

Answer:

$3

Step-by-step explanation:

Given that:

Park charge for one round = $19

Reduced fee for every additional round

Number of rounds played by Tom = 6

Amount paid = $34

Amount left after 1 round :

Amount paid - first round charge

$34 - $19 = $15

Number of rounds left = (6 - 1) = 5

Charge per additional round :

$15 / 5 = $3

3 0
3 years ago
7.24 + 5.3 = 3m<br><br> what is the true answer ?
laiz [17]

Answer:

7.24 + 5.3 = 3m

=> 3m = 12.54

=> m = 12.54/3

=> m = 4.18

<h2>Answer = 4.18</h2>

8 0
2 years ago
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