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Digiron [165]
3 years ago
8

A rectangle is 12 feet long and 5 feet wide. If the length of the rectangle is increased by 25% and the width is decreased by 20

%, what is the change in the area of the rectangle? The change in the area of the rectangle is
Mathematics
1 answer:
Evgen [1.6K]3 years ago
7 0

Answer:

no change in area

Step-by-step explanation:

The original area is

A = 12*5 = 60 ft^2

The new length and width

l = 12 + .25 (12) = 12+3 =15

w = 5 - .2 (5) =5-1 = 4

The new area is

A = l*w =15*4 = 60 ft^2

The area is the same

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The area of a rectangular field is 6840 m2. If the width of the field is 72m , what is its length?
IgorLugansk [536]

Answer:

I believe that the answer is 95 meters.

Explanation:

Okay, so to solve this question, you must know the formula to solve for the area of a rectangle/square.

<em>Area of a rectangle/square - </em><em>l x w</em>

<em />

In this question, you can see the the width (72 m) and the area (6840 m²) is already given. What you can do in this situation is to use the opposite operator (division) to solve for the length of the rectangular field.

<em>6840 ÷ 72 = </em><em>95</em>

You can always double check to see if the number is correct.

<em>A = l x w</em>

<em>= 72 m x 95 m</em>

<em>= </em><em>6840 m</em>²

Really hope this helped. :)

6 0
3 years ago
1.How many more people prefer math to history?
slega [8]

Answer:

1) 9. 2) 11. 3) art and science

This is your answer ☺️☺️☺️

8 0
3 years ago
Read 2 more answers
If the product of two integers is positive, their signs are positive or negative
worty [1.4K]

Answer:

It could be both 2 positives, or 2 negatives.

Step-by-step explanation:

This is because a negative times a negative is a positive, and a positive times a positive is a positive.

7 0
3 years ago
What is -2.4x +3.8x-x<br>​
maksim [4K]
The answer is .4x because -3.4x+3.8x
4 0
3 years ago
The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
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