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Iteru [2.4K]
3 years ago
7

How many moles of aluminum oxide al2o3 are in a sample with a mass of 204.0

Chemistry
2 answers:
Leviafan [203]3 years ago
6 0

Answer:

2 moles

Explanation

Molecular mass of Al : 26.981539 u

Molecular mass of O: 15.999 u

The molecular mass of Al₂O₃ is:

= 101.960078 u

This can be approximated to 102 u.

1mole weighs 102 u

So, 2moles will weigh 2*102 = 204 u

erik [133]3 years ago
3 0

Answer:

2 moles

Explanation:

Let us first start by calculating the molecular mass of Al₂O₃.

The mass of a mole of any compound is called it's molar mass. 1 molar mass 6.02 X 10²³, or Avogadro's number, of compound entities.

Say, 1 mole of Al₂O₃ has 6.02 X 10²³ of Al₂O₃ molecules/atoms. It also has 2*6.02 X 10²³ number of Al atoms and 3*6.02 X 10²³ number of O atoms.

Molecular mass of Al : 26.981539 u

Molecular mass of O: 15.999 u

Therefore, molecular mass of Al₂O₃ is:

= (2*26.981539) + (3*15.999) u

= 101.960078 u

This can be approximated to 102 u.

1mole weighs 102 u

So, 2moles will weigh 2*102 = 204 u

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Answer:

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Explanation:

Chemical equation:

Mg + O₂  →  MgO

Balanced chemical equation:

2Mg + O₂  →  2MgO

The balanced equation s given above and it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Steps to balanced the equation:

Step 1:

Mg + O₂  →  MgO

Mg = 1         Mg = 1

O = 2           O = 1

Step 2:

2Mg + O₂  →  MgO

Mg = 2         Mg = 1

O = 2           O = 1

Step 3:

2Mg + O₂  →  2MgO

Mg = 2         Mg = 2

O = 2           O = 2

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