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Veseljchak [2.6K]
3 years ago
9

A polonium atom has 84 protons, 124 neutrons, and 84 electrons. What will it change to during alpha decay? A. A lead atom with 8

2 protons, 122 neutrons, and 84 electrons B. A bismuth atom with 83 protons, 123 neutrons, and 84 electrons C. A polonium atom with 84 protons, 124 neutrons, and 85 electrons D. An astatine atom with 85 protons, 123 neutrons, and 84 electrons
Chemistry
2 answers:
Vlada [557]3 years ago
6 0

Answer: Option (A) is the correct answer.

Explanation:

An alpha particle is a helium atom that is represented as ^{4}_{2}He.

Therefore, when an alpha decay occurs if polonium atom has 84 protons, 124 mass, and 84 electrons. Then the reaction will be as follows.

            ^{124}_{84}Po \rightarrow ^{120}_{82}A + ^{4}_{2}He

An element with atomic number 82 is lead.

Thus, we can conclude that when a polonium atom has 84 protons, 124 mass, and 84 electrons then it will change to a lead atom with 82 protons, 122 mass, and 82 electrons during alpha decay.

77julia77 [94]3 years ago
3 0
I think the correct answer would be A. When a polonium atom with 84 protons, 124 neutrons, and 84 electrons undergoes alpha decay, a lead atom would be produced with 82 protons, 122 neutrons, and 84 electrons together with an alpha particle having two protons and two neutrons.
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0.25 mol of nitric acid is used to make a 0.10 M nitric acid solution. What is the total volume of nitric acid in liters
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Answer:

2.5 L will be the volume of HNO₃

Explanation:

To find out the total volume of nitric acid in liters we begin from molarity.

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As we used 0.25 moles of nitric, let's determine the volume by a rule of three:

0.10 moles of nitric acid are contained in 1L of solution

0.25 moles of nitric acid will be contained in (0.25 . 1) / 0.1 = 2.5 L

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8 0
4 years ago
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3 years ago
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Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
Misha Larkins [42]
Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

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Have a nice day!
8 0
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