2.0 grams of ZnSO4 reacts completely with Li2CO3; how many grams of Li2SO4 would be produced?

1 answer:

3 0

Moles of ZnSO4 = Mass/Mr
= 2/(65.4 + 32.1 + (16 x 4))
= 0.012383.... mol

Since there is no chemical equation provided, I will assume that the ratio of ZnSO4:Li2CO3 is 1:1

Therefore there are 0.012383 mil of Li2SO4 as well
So the mass would be Moles x Mr = 0.012383.... x ((6.9 x 2) +32.1 + (4x16))
= 1.360 g of Li2SO4 produced

You might be interested in

What is the best description of the relationship between emerging scientific ideas and open-mindedness?

valentinak56 [21]

Answer:

The main relationship between emerging scientific ideas and open-mindedness is that for many new ideas to be accepted a population has to have an open mind, otherwise the new ideas are rejected without thought.

Explanation:

7 0

3 years ago

Which of the following compounds has a lower boiling point? Li2O H₂O KCI MgCl2

Kamila [148]

Pretty sure it’s H2O

6 0

3 years ago

Which of the following is equal to 2.0 liters? 200 mL 2,000 cm3 20 m3 20,000 mm3

ololo11 [35]

It equals 2000 but in this case it would be 20,000mm3

4 0

3 years ago

Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2NH3(g) 3N2O(g)4N2(g) 3H2O

trasher [3.6K]

Answer: $\Delta H^{0} = -879.15 kJ/mol$

Explanation: Heats of formation is the amount of heat necessary to create 1 mol of a compound from its molecular constituents. The basic conditions the substance is formed is at standard conditions: 1 atm and 25°C. Each compound has its own heat of formation per mol of compound (kJ/mol), but to an element is assigned a value of zero.

Standard Enthalpy Change is defined as the heat absorbed or released when a reaction takes place. It can be positive or negative, which means reaction is endothermic or exothermic, respectively.

Enthalpy change is calculated as the difference between the sum of heat formation of products and the sum of heat formation of the reactants:

$\Delta H^{0}=\Sigma H^{0}_{f}_{(products)}-\Sigma H^{0}_{f}_{(reactants)}$