Answer : The concentration of at equilibrium is 0 M.
Solution : Given,
Concentration of = 0.0200 M
Concentration of = 1.00 M
The given equilibrium reaction is,
Initially conc. 0.02 1.00 0
At eqm. (0.02-x) (1.00-3x) x
The expression of will be,
By solving the term, we get:
Concentration of at equilibrium = 0.02 - x = 0.02 - 0.02 = 0 M
Therefore, the concentration of at equilibrium is 0 M.
Answer:
4. 1; 6; 2 — synthesis
Explanation:
<u>Decomposition reaction </u>is defined as the reaction in which a single large substance breaks down into two or more smaller substances.
<u>Single displacement </u>reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.
The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.
<u>Synthesis reaction</u> is defined as the reaction in which smaller substances combine in their elemental state to form a larger substance.
The unbalanced combustion reaction is shown below as:-
On the left hand side,
There are 4 phosphorus atoms and 1 calcium atom
On the right hand side,
There are 2 phosphorus atoms and 3 calcium atoms
Thus,
Right side, must be multiplied by 2 to balance phosphorus.
Left side, is multiplied by 6 so to balance the whole reaction.
Thus, the balanced reaction is:-
Thus, answer:- 4. 1; 6; 2 — synthesis