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3 years ago

Consider what you learned about change in this lesson and in the story. Think about the theme of "people can change for

2 answers:

7 0

At the beginning of the story, Jimmy Valentine is eager to get back to his old ways. He packs his suitcase of “burglar’s tools” and leaves town. However, when he reaches Elmore, he falls in love with Annabel Adams. He “looked into her eyes, forgot what he was, and became another man.” His love for Annabel drives him to change his ways and live a decent life. He is able to change for the better for her.

Harlamova29_29 [7]3 years ago

7 0

Answer:

Similarly, Ben Price believes at the beginning of the story that Jimmy has “resumed business.” He thinks Jimmy is responsible for the string of bank robberies. He believes that Jimmy wants to marry Annabel, a “banker’s daughter,” only to rob the bank. However, he sees Jimmy rescue the girl trapped in the safe. He sees that Jimmy doesn’t take anything else from the safe. Price believes Jimmy has changed for the better.

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234 divided by 33 I really need this answer doing school work

Elodia [21]

Answer:

7.0909090909 hope this helps!!

4 0

3 years ago

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What is f(x) = –4x2 + 24x + 13 written in vertex form? f(x) = –4(x – 6)2 + 23 f(x) = –4(x – 6)2 + 7 f(x) = –4(x – 3)2 + 4 f(x) =

nika2105 [10]

We have that
f(x) = –4x² + 24x + 13

we know that

The vertex form for a parabola that opens up or down is:

f(x) = a(x - h)^2 + k

in the given equation, a=-4, therefore we add zero to the original equation in the form of 4h²−4h²
f(x) = –4x² + 24x + 4h²−4h² +13
Factor 4 out of the first 3 terms and group them
f(x) = –4*(x² -6x +h²) +4h² +13
We can find the value of h by setting the middle term equal to -2hx
−2hx=−6x
h=3 and 4h²=36
f(x) = –4*(x² -6x +9) +36 +13

we know that the term (x² -6x +9) is equals to------> (x-3)²
so
f(x) = –4*(x-3)² +49

the answer is
f(x) = –4*(x-3)² +49

4 0

3 years ago

Find f(b-2) if f(x) = x^2-6x+1

jasenka [17]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The equivalent expression is ~

$f(b - 2) = {b}^{2} - 10b + 17$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's evaluate f(b - 2) ~

$f(x) = {x}^{2} - 6x + 1$

$f(b - 2) = (b - 2) {}^{2} -6 (b - 2) + 1$

$\mathcal{ {f(b - 2) = {b}^{2} + 2 {}^{2} - (2 \times b \times 2) - 6b + 12}}$

$f(b - 2) = {b}^{2} + 4 - 4b - 6b + 12 + 1$

$f(b - 2) = {b}^{2} - 10b + 17$

4 0

3 years ago

Read 2 more answers

I need the answer quickly

sweet [91]

Answer:

scatter plot 3

Step-by-step explanation:

No correlation exists when there is no relationship between two variables. For example there is no relationship between the x-axis to the y-axis while the other plots has noticeable linear correlation.

6 0

2 years ago

How do you get an equation to solve for all 3 sides of a triangle?

slavikrds [6]

In your solving toolbox (along with your pen, paper and calculator) you have these 3 equations:

1. The angles always add to 180°:

A + B + C = 180°

When you know two angles you can find the third.

2. Law of Sines (the Sine Rule):

Law of Sines

When there is an angle opposite a side, this equation comes to the rescue.

Note: angle A is opposite side a, B is opposite b, and C is opposite c.

3. Law of Cosines (the Cosine Rule):

Law of Cosines

This is the hardest to use (and remember) but it is sometimes needed

to get you out of difficult situations.

It is an enhanced version of the Pythagoras Theorem that works

on any triangle.

With those three equations you can solve any triangle (if it can be solved at all).

Six Different Types (More Detail)

There are SIX different types of puzzles you may need to solve. Get familiar with them:

1. AAA:

This means we are given all three angles of a triangle, but no sides.

AAA Triangle

AAA triangles are impossible to solve further since there are is nothing to show us size ... we know the shape but not how big it is.

We need to know at least one side to go further. See Solving "AAA" Triangles .

2. AAS

This mean we are given two angles of a triangle and one side, which is not the side adjacent to the two given angles.

AAS Triangle

Such a triangle can be solved by using Angles of a Triangle to find the other angle, and The Law of Sines to find each of the other two sides. See Solving "AAS" Triangles.

3. ASA

This means we are given two angles of a triangle and one side, which is the side adjacent to the two given angles.

ASA Triangle

In this case we find the third angle by using Angles of a Triangle, then use The Law of Sines to find each of the other two sides. See Solving "ASA" Triangles .

4. SAS

This means we are given two sides and the included angle.

SAS Triangle

For this type of triangle, we must use The Law of Cosines first to calculate the third side of the triangle; then we can use The Law of Sines to find one of the other two angles, and finally use Angles of a Triangle to find the last angle. See Solving "SAS" Triangles .

5. SSA

This means we are given two sides and one angle that is not the included angle.

SSA Triangle

In this case, use The Law of Sines first to find either one of the other two angles, then use Angles of a Triangle to find the third angle, then The Law of Sines again to find the final side. See Solving "SSA" Triangles .

6. SSS

This means we are given all three sides of a triangle, but no angles.

SSS Triangle

In this case, we have no choice. We must use The Law of Cosines first to find any one of the three angles, then we can use The Law of Sines (or use The Law of Cosines again) to find a second angle, and finally Angles of a Triangle to find the third angle.

7 0

3 years ago

Read 2 more answers