Question

Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth.

Answer 1

Answer:

3.6 units

Step-by-step explanation:

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is:

$PQ=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2 }$

$PQ=\sqrt{(4-1)^2+(3-5)^2}$

$PQ=\sqrt{(3)^2+(-2)^2}$

$PQ=\sqrt{9+4}$

$PQ=\sqrt{13}$

$PQ=3.6 units$

Thus, the distance between the given two points is 3.6 units.

Answer 2

Using distance formula =√(5-3)sq+(1-4)sq
=√4+9
=√13