Answer:
3
Step-by-step explanation:
an integer is a number without any decimals or fractions like 7 or 3.
2x+9=6x+7. 2x+2=6x. 2=4x. X=1/2 a year
The inverse of the equation y = x² - 4, x≤ 0 is 
<h3>How to determine the inverse of the equation?</h3>
The equation is given as:
y = x² - 4, x≤ 0
Swap the x and y values
x = y² - 4
Add 4 to both sides
y² = x + 4
Take the square root of both sides

Hence, the inverse of the equation y = x² - 4, x≤ 0 is 
Read more about inverse equations at:
brainly.com/question/11302699
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Answer:
![\sqrt[3]{192} x^{\frac{3}{5} }y^{\frac{3}{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B192%7D%20x%5E%7B%5Cfrac%7B3%7D%7B5%7D%20%7Dy%5E%7B%5Cfrac%7B3%7D%7B8%7D%20%7D)
Step-by-step explanation:
You have to simplify all of the terms individually
![\sqrt[3]{192} = 5.769](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B192%7D%20%3D%205.769)
Since that isn't a whole number, it doesn't simplify
Use the root to exponent rule for the variables
![\sqrt[3]{x^{5} } =x^{\frac{3}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B5%7D%20%7D%20%3Dx%5E%7B%5Cfrac%7B3%7D%7B5%7D%20%7D)
![\sqrt[3]{y^{8} } =y^{\frac{3}{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E%7B8%7D%20%7D%20%3Dy%5E%7B%5Cfrac%7B3%7D%7B8%7D%20%7D)
Then put them all together to get
![\sqrt[3]{192} x^{\frac{3}{5} }y^{\frac{3}{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B192%7D%20x%5E%7B%5Cfrac%7B3%7D%7B5%7D%20%7Dy%5E%7B%5Cfrac%7B3%7D%7B8%7D%20%7D)
Make sure the variables aren't under the root when you give your answer
I hope this helps!
pls mark brainliest